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insens350 [35]
3 years ago
10

The slope of a line is 2. The y-intercept of the line is –6. Which statements accurately describe how to graph the function? Loc

ate the ordered pair (0, –6). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points. Locate the ordered pair (0, –6). From that point on the graph, move up 2, left 1 to locate the next ordered pair on the line. Draw a line through the two points. Locate the ordered pair (–6, 0). From that point on the graph, move up 2, right 1 to locate the next ordered pair on the line. Draw a line through the two points. Locate the ordered pair (–6, 0). From that point on the graph, move up 2, left 1 to locate the next ordered pair on the line. Draw a line through the two points.
Mathematics
1 answer:
MrMuchimi3 years ago
7 1

Answer:

Step-by-step explanation:

Brianna bts
2 years ago
There is no awnser this isn't helpful
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GIVING BRAINLIEST Graph and solve the inequality y>-|x-5|-1
MakcuM [25]

Answer:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

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We can now plot the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

The boundary line will be solid because the inequality operator contains an "or equal to" clause.

graph{(x^2+(y-5)^2-0.125)((x+2)^2+(y-3)^2-0.125)(y-x-5)=0 [-20, 20, -10, 10]}

Now, we can shade the left side of the line.

graph{(y-x-5) >= 0 [-20, 20, -10, 10]}

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I need help with this asap! i will give brainliest :) (image included)
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Jessica spent 2/5 of her money going to the movies. Then she babysat her brother and earned fifteen more dollars. If she ended u
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Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


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The area of a rectangle is 4.9 square units. The length is 2.5 units and the width is y units. What is the value of y?
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1.96, if you multiply that by the length, (which is 2.5) then you will get the area of 4.9 hope this helps
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