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ExtremeBDS [4]
3 years ago
11

1 point

Mathematics
2 answers:
Feliz [49]3 years ago
4 0

Answer:36

Step-by-step explanation:

90/10= 9 9x4=36

Mama L [17]3 years ago
4 0
36 dollars for the 4 tickets because each ticket is 9 dollars and 9x4 is 36
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Help please! Calculate the exact value of cos (a-b) given that sin a= 12/13 with pi/2
zloy xaker [14]

Answer:

56/65

Step-by-step explanation:

First, we know that cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

We know what sin(a) and sin(b) are, and to get cos(a), we can take the equation sin²a + cos²a = 1

Thus,

(12/13)² + cos²a = 1

1 - (12/13)² = cos²a

1- 144/169 = cos²a

cos²a = 25/169

cos(a) = 5/13

Similarly,

(3/5)² + cos²b = 1

1 - (3/5)² = cos²b

1 - 9/25 = cos²b

cos²b = 16/25

cos(b) = 4/5

Our answer is

cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

cos(a-b)  = (5/13)(4/5) + (12/13)(3/5)

cos(a-b)  = 20/65 + 36/65

cos(a-b)  = 56/65

4 0
3 years ago
What number represents the minimum (least)?<br>1.10<br>2.14<br>3.16<br>4.20<br>5.29​
Vinvika [58]

Answer:

10

Step-by-step explanation:

10 is the least of the numbers, it is the lowest

10<14,16,20,29

4 0
3 years ago
Read 2 more answers
will has $1.67 in pennies and quarters. His number of pennies is five more than twice the number of quarters. How many pennies d
Lena [83]

p = pennies


q= quarters


p = 2q+5   (1)


.25q+.01p=1.67   (2)


substitute  the equation for pennies (1) into the 2nd equation


.25q+.01(2q+5)=1.67


distribute


.25q +.02q +.05 = 1.67


combine like terms


.27q +.05 =1.67


subtract .05 from each side


.27q = 1.62


divide by .27


q=6


p=2q+5


p=2(6)+5


p=12+5


p=17


There are 6 quarters and 17 pennies





4 0
3 years ago
12:0.48<br> what is the value of the expression
Mariulka [41]
Explanation:

Answer:
12.48 i think
3 0
3 years ago
The formula c=<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%20%20%7D%20" id="TexFormula1" title=" \sq
Amiraneli [1.4K]

Answer:

The required equation is b=\sqrt{c^2-a^2}

Step-by-step explanation:

Consider the provided equation.  

c= \sqrt{a^{2}+b^{2}}

Solve the equation for b.

Square both the sides.

c^2= a^{2}+b^{2}

Subtract a² from both the sides.

c^2-a^2= b^{2}

Square root both the sides.

b=\sqrt{c^2-a^2}

Hence the required equation is b=\sqrt{c^2-a^2}

6 0
3 years ago
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