Answer:
1.7 × 10⁻⁴
Step-by-step explanation:
The question relates to a two sample z-test for the comparison between the means of the two samples
The null hypothesis is H₀: μ₁ ≤ μ₂
The alternative hypothesis is Hₐ: μ₁ > μ₂

Where;
= 13.5
= 12
σ₁ = 2.5
σ₂ = 1.5
We set our α level at 0.05
Therefore, our critical z = ± 1.96
For n₁ = n₂ = 23, we have;

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96
Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983
Therefore;
The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.
Answer:
y + 7 = -
(x - 1)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
Where m is the slope and (a, b) a point on the line
Here m = -
and (a, b) = (1, - 7), thus
y - (- 7) = -
(x - 1), that is
y + 7 = -
(x - 1) ← in point- slope form
Answer:
S12=855735
Step-by-step explanation:
if the 3rd term is 45 then,
formula: Sn=ar^n-1
S12=5*3^12-1
S12=5*3^11
S12=5*177147
S12=855735
What you can do in this case is a rule of three to determine the length of each bow.
We have then:
1/4 ---> 2
x ------> 1
Clearing x we have:
x = (1/2) * (1/4)
x = 1/8
Answer:
the length of ribbon in each bow is
x = 1/8
Equivalently:
x = (1/4) / 2
Option 3
14/2.99=1/x
14x=2.99(1)
x=2.99/14
x=0.213571429