Answer:
40.25 I guess
Step-by-step explanation:
Answer:
The required probability is 0.55404.
Step-by-step explanation:
Consider the provided information.
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.
Average error for 7 pages booklet and 5 pages booklet series is:
λ = 0.2×7 + 0.3×5 = 2.9
According to Poisson distribution: 
Where
is average number of events.
The probability of more than 2 typographical errors in the two booklets in total is:

Substitute the respective values in the above formula.



Hence, the required probability is 0.55404.
If David has 83 CD's, and each rack holds 25, then David would need 4 racks. 4 racks will hold up to 100 CD's, where as 3 racks would only hold 75.
I'm not sure what 'Lin' has to do with this equation, but if she has 6 racks full of CD's then in total she has 150 CD's.
Hope this helps! :)
Answer:
life changes over time?
Step-by-step explanation:
sorry if it is wrong. I havent done this yet