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2 years ago

Shares of AT&T stock were purchased for $8,250. What is the cost of ten shares?

Mathematics

1 answer:

Dahasolnce [82]2 years ago

5 0

Answer:

$82,500

Step-by-step explanation:

Since each share is 8250 and we want to find to find 10 shares, we can do 8250 (price of each share) x 10 (amount of shares) and we get $82500

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An aluminum can has a capacity of 2.37 L. What is the capacity of the can in milliliters?

sasho [114]

Answer:

2,370 mL

Step-by-step explanation:

1000mL = 1 L, so I multiplied 1000 by 2.37

If they ask for it to be set up as a proportion, I would write 1/1000 = 2.37/x and cross multiply. x = 2,370

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2 years ago

What is the purpose of a cash budget?

Shtirlitz [24]

The purpose of a cash budget is to help financial managers to get a better understanding of the timing of cash flows.
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3 years ago

PLEASE HELP IM SO STUCK 20 POINTS

prohojiy [21]

Answer: X = 2

Step-by-step explanation: The correct answer to this question is that x=2. Regardless of what point you go to on the line, it always has a value of 2 because it is going vertically (up and down) at 2.

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3 years ago

Marvin lives in Stormwind City and works as an engineer in the city of Ironforge. In the morning, he has 333 transportation opti

sukhopar [10]

The event "Atleast once" is the complement of event "None".

So, the probability that Marvin teleports atleast once per day will the compliment of probability that he does not teleports during the day. Therefore, first we need to find the probability that Marvin does not teleports during the day.

At Morning, the probability that Marvin does not teleport = 2/3

Likewise, the probability tha Marvin does not teleport during evening is also 2/3.

Since the two events are independent i.e. his choice during morning is not affecting his choice during the evening, the probability that he does not teleports during the day will be the product of both individual probabilities.

So, the probability that Marvin does not teleport during the day = $\frac{2}{3}*\frac{2}{3}=\frac{4}{9}$

Probability that Marvin teleports atleast once during the day = 1 - Probability that Marvin does not teleport during the day.

Probability that Marvin teleports atleast once during the day = $1-\frac{4}{9}=\frac{5}{9}$

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3 years ago

HELP PLS ANSWER ASAP DUE TOMARROW

damaskus [11]

Answer:

they need to sell 15,000 because 42 percent of 15,00 is 6,300+2500=800

the inequality should be. 2500+0.42s≥8,800

and the number line should have a closed point on 15,000 with the line pointing to the right

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3 years ago