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valina [46]
2 years ago
8

Determine the domain of the following graph:

Mathematics
1 answer:
Kipish [7]2 years ago
4 0
-8 (is less than or equal to) x ( which is less than) 3
Or [-8,3)
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Find a point-slope form for the line with slope 1/5 and passing through the point (-2,- 7).
snow_tiger [21]

Answer:

point slope form is y-y1 = m(x-x1) which is y+7= 1/5(x + 2)

3 0
3 years ago
Find the GCF 15, 18, 30
katen-ka-za [31]
You need to find the prime factors of each term in order to find the greatest common factor.  

The answer is 3. 
3 0
3 years ago
Ignoring those who said they weren't sure, there were 297 men asked, and 183 said yes, they had driven a car when they probably
USPshnik [31]

Answer:

z=\frac{0.616-0.5}{\sqrt{\frac{0.5(1-0.5)}{297}}}=3.998  

p_v =2*P(z>3.998)=0.0000639  

With the most common significance levels used \alpha= 0.1, 0.05, 0.01 we see that the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can say that the true proportion is significantly higher than 0.5

Step-by-step explanation:

Information given  

n=297 represent the random sample of male taken

X=183 represent the  men who said yes, they had driven a car when they probably had too much alcohol

\hat p=\frac{183}{297}=0.616 estimated proportion of men who said yes, they had driven a car when they probably had too much alcohol

p_o=0.5 is the value that we want to test

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Hypothesis to test

We need to conduct a hypothesis in order to test the claim that the majority of men in the population (that is, more than half) would say that they had driven a car when they probably had too much alcohol, and the system of hypothesis are:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

After replace we got:

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.616-0.5}{\sqrt{\frac{0.5(1-0.5)}{297}}}=3.998  

Decision

We have a right tailed test so then the p value would be:  

p_v =2*P(z>3.998)=0.0000639  

With the most common significance levels used \alpha= 0.1, 0.05, 0.01 we see that the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis and we can say that the true proportion is significantly higher than 0.5

7 0
3 years ago
Hill’s garden has lots of apple trees. 140 apples fall on ground in 35 seconds. How many apples fall in one second?
IRISSAK [1]
4 Apple would fall in 1 second
3 0
4 years ago
The central limit Theron defines large samples as having at least 36 elements true or false ?
Oksanka [162]

This statement is false

5 0
3 years ago
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