The first one is categorical data
the second one is discrete numerical
and the third one is continuous numerical
i hope this helps you
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Answer:
Step-by-step explanation:
4) x² - 14x + 48
We would find two numbers such that their sum or difference is -14x and their product is 48x².
The two numbers are - 6x and - 8x. Therefore,
x² - 6x - 8x + 48
x(x - 6) - 8(x - 6)
(x - 8)(x - 6)
5) 2x² + 21x - 11
We would find two numbers such that their sum or difference is 21x and their product is - 22x².
The two numbers are 22x and - x. Therefore,
2x² + 22x - x - 11
2x(x + 11) - 1(x + 11)
(2x - 1)(x + 11)
6) 5a² - 125
5 is a common factor. So we would factorize 5. It becomes
5(a² - 25)
Simplifying further, it becomes
5(a + 5)(a - 5)
Well I’m not 100 percent sure but I believe it’s b
Answer:
Step-by-step explanation:
a = 5
r = -5
n = 9
t_9 = a r^(n - 1)
t_9 = (-1)^n*5 (-5) ^ 8
t_9 = (-1)^9 * 5 * (-5) ^8
t_9 = -1 ( 1953125)
t_9 = - 1953125
