1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zanzabum
3 years ago
7

Please help ASAP!

Computers and Technology
2 answers:
AysviL [449]3 years ago
4 0

Answer:

GIVE this man Brainliest!

Explanation:

soldier1979 [14.2K]3 years ago
3 0
The answer to that would be D 120,120 pls ease mark me bralieat I had work hard on this one
You might be interested in
Write a program that reads students’ names followed by their test scores. The program should output each student’s name followed
bekas [8.4K]

Answer:

See explaination

Explanation:

#include <iostream>

#include <iomanip>

#include <fstream>

#include <string>

using namespace std;

void readStudentsData();

void levels(int&,int&,int&);

int main()

{

string studentsName[50];

int grade[50];

int highestScore = 0;

int belowAverage = 50;

int countStudents = 0;

int sum = 0;

int score[5]=

double average = 0;

ifstream infile;

ofstream outfile;

void readStudentsData();

infile.open("c:\\Data.txt");

int numOfStudents = 0;

infile >> studentsName[numOfStudents] >> grade[numOfStudents];

While (infile && numOfstudents < 50)

{

numOfStudents++;

infile >> studentsName[numOfStudents] >> grade[numOfStudents};

}

if (!infile)

{

cout << "File does not open." << endl;

return 1;

}

outfile.open("c:\\average.out");

outfile << fixed << showpoint;

outfile << setprecision(2);

infile >> studentsName;

infile >> score1 >> score2 >> score3 >> score4 >> score5 >>;

outfile << left << setw(20) << "Students Name"

<< setw(5) << "Score 1" << setw(5) << "Score 2"

<< setw(5) << "Score 3" << setw(5) << "Score 4"

<< setw(5) << "Score 5" << setw(5) << "Grade"

<< setw(5) << "Average" << setw(5) << "Below average"

<< setw(5) << "Highest" << endl;

if (average >= 90)

cout << "A" << endl;

else if (average >= 80)

cout << "B" << endl;

else if (average >= 70)

cout << "C" << endl;

else if (average >= 60)

cout << "D" << endl;

else

cout << "F" << endl;

}

average = static_cast<double>(score1+score2+score3+score4+score5) /5;

void level(int &highestScore,int &belowAverage,int &sum);

{

int level,high = 0,low = 17;

infile >> level;

while(level!=-1)

{

sum = sum + level;

if (level > high)

{

high = level;

infile >> level;

}

else

if (level < low)

{

low = level;

infile >> level;

}

else

if infile >> level;

}

outfile << ' ' << high;

else

if (high > highestScore)

highestScore=high;

else

if (low < belowAverage)

belowAverage=low;

}

do

{

cout << "Students Name: ";

cin >> name

cout << "Input score: " << endl;

cin >> score1>> score2>> score3>> score4>> score5;

cout << Students Name << Highest score);

}

While (highest score !=0);

infile.close();

outfile.close();

return 0;

}

5 0
3 years ago
A prime number is an integer that is divisible only by 1 and by itself. Write a program that: 1. Takes a number as an input. 2.
Alexandra [31]

Answer:

is c

Explanation:

8 0
2 years ago
Kyra is teaching a photography class. She would like her students to share photos. She would also like the students to be able t
SIZIF [17.4K]

Answer:

A blog.

Explanation:

A blog can be defined as an informative or discussion-based website that is updated regularly and published over the internet. The informations that are posted on a blog are usually done chronologically and it includes pictures, videos, music, movies, novels, etc.

In this scenario, Kyra is teaching a photography class. She would like her students to share photos, be able to review other students' photos and offer feedback.

Hence, the technology Kyra should use is a blog because it would avail the users (students) to post photos, make comments on blog posts and review items posted by others.

6 0
2 years ago
Write a program to output a big A like the one below
Gelneren [198K]

hope this helps, i'm a beginner so this might not be the most concise method

3 0
3 years ago
Utilizando o padrão de medidas e unidades do National Institute of Standards and Technology, em que 1 KB é igual a 1.000 Bytes,
Tanya [424]

Segundo o padrão da  National Institute of Standards and Technology a  alternativa correta é a letra E) 400 músicas.  Segundo o padrão disposto acima, dois Giga Bytes equivalem à dois mil Mega Bytes, assim, se cada música tem exatos 5MB, podemos chegar ao total de músicas que podem ser gravadas em um PenDrive de 2GB livres do seguinte modo :

x=\frac{2000 MB}{5MB};x=400

 A evolução da microeletrônica possibilitou uma capacidade de armazenamento cada vez maior a cada ano. O desenvolvimento de novas tecnologias na área permite também que os produtores possam produzir músicas, fotos e vídeos com cada vez mais qualidade (consequentemente mais pesada).

5 0
2 years ago
Other questions:
  • DJ wants to see how his document will look when printed. Where would he find the button to see the document in print view? the P
    5·2 answers
  • To make sure that you do not get too tired when typing for long periods, how often should you get up and stretch? Every 15 minut
    9·1 answer
  • An organization uses SAP financial management software to store accounting details and Microsoft CRM software to record customer
    12·1 answer
  • Why is compression a "hard problem" for computers? Draw on your own experience compressing text with the text compression widget
    12·1 answer
  • At what x position are the ellipses drawn??? thanks ♡​
    6·1 answer
  • What best describes presentation software?
    14·1 answer
  • Describe any five GSM PLMN basic services?
    10·1 answer
  • ¿Quién recibe la orden de ejecución de un programa enviada por el usuario?
    9·1 answer
  • The notes added to slides can be seen during the presentation. TRUE OR FALSE​
    13·1 answer
  • Figure out what this says:<br><br> ?driew tib a kool ti seoD
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!