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ollegr [7]
3 years ago
15

Write an equation for the transformed logarithm shown below, that passes through (2,0) and (-2,2)

Mathematics
1 answer:
navik [9.2K]3 years ago
8 0

Answer:

The answer is y = -1/2x + 1.  Let me know if you want this in standard or point-slope form.

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Part A: 180 = 4m + b B = 180 + 4m 325 = 9m + b 325 - 180 = 9m - 4m 5m = 145 m = 29 b = 180 + 4(29) = 64 y = 29x + 64
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3 years ago
Given that f(x) = 6x + 2 and g(x) =2x+4 over 5 solve for g(f(1))
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F(1)=6(1)+2
= 6+2
=8

g(f(1))= 2x/5 +4/5
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= 16/5 +4/5
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3 years ago
Use this graph and the shapes shown to complete the tasks in this activity.
Kruka [31]

Answer: A reelection across the Y axis, then a reflection across the X axis.

Step-by-step explanation:

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2 years ago
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The box plots below show the average gas mileage, in miles per gallon, of the cars sold at a dealership in June and in
LekaFEV [45]

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The interquartile range for December should be 21 minus 18 = 3.

Step-by-step explanation:

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3 years ago
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A function is given. h(t) = t2 + 3t; t = −1, t = 2
Arlecino [84]

Answer:

(a) The net change of the function is 12.

(b) The average rate of change of the function 4.

Step-by-step explanation:

The average rate of change of function f(x) over the interval a\leq x\leq b is given by this expression:

average rate of change =  \frac{net \:change \:in \:y}{change \:in \:x} = \frac{f(b)-f(a)}{b-a}

It is a measure of how much the function changed per unit, on average, over that interval.

Given:

h(t)=t^2+3t\\\\t=-1\\t=2

(a) To find the net change of the function, first we calculate the values of h(2) and h(-1)

h(-1)=(-1)^2+3(-1)=-2\\\\h(2)=(2)^2+3(2)=10

The net change is simply the difference

h(2)-h(-1)=10-(-2)=12

(b) The average rate of change takes the net change and divides it by the change in the t value.

\frac{12}{2-(-1)} =\frac{12}{3}=4

5 0
3 years ago
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