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fomenos
3 years ago
5

What is the value of this expression when t= -12? -311-8] + 1.5

Mathematics
1 answer:
Leni [432]3 years ago
5 0

Answer:

2

Step-by-step explanation:

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Solve the equation.<br><br> 5=w2.2
Sedaia [141]

Answer:

The answer is about 2.27

Step-by-step explanation:

Hope this help <3

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3 years ago
The graph of an exponential function, f(x), is shown. Move numbers to the blanks to describe how f(x) increases and grows over d
yawa3891 [41]

By looking at the graph we can see that f(x) increase by 1 (on the vertical axis . or y-axis ) from 2 to 3, over the interval 0 to 1 ( horizontal axis, or x-axis)

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by 4 over the interval 2 to 3.

And by 8 over the interval 3 to 4.

Therefore this exponential function grows by a factor of 2 (since it doubles every by every interval of 1)

6 0
1 year ago
Consider this equation: –2x – 4 + 5x = 8 Generate a plan to solve for the variable. Describe the steps that will be used.
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We are given the function <span>–2x – 4 + 5x = 8  and is asked in the problem to solve for the variable x in the function. In this case, we can first group the like terms and put them in their corresponding sides:

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Then, do the necessary operations.

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6 0
4 years ago
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I need help with solving a system of equations using elimination
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Step-by-step explanation:

7 0
3 years ago
Factor x3y6 + 27z42. (xy3 + 3z39)(x2y9 – 3xy3z39 + 9z1,521) (xy3 + 3z39)(x2y6 – 3xy3z39 + 9z78) (x3y6 + 27z42)(x6y12 – 27x3y6z42
Licemer1 [7]

Answer:

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})

Step-by-step explanation:

Given

x^3y^6 + 27z^{42

Required

Factor

Express both terms as a cube

x^3y^6 + 27z^{42} = (xy^2)^3 + (3z^{14})^3

Let

a =(xy^2)

b = (3z^{14})

So:

x^3y^6 + 27z^{42} = a^3 + b^3

Using sum of cubes:

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

So:

x^3y^6 + 27z^{42} = (a + b)(a^2 - ab + b^2)

Substitute in, values of a and b

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})((xy^2)^2 - (xy^2)*(3z^{14}) + (3z^{14})^2)

x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})

5 0
3 years ago
Read 2 more answers
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