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3 years ago

Solve the following system of equations algebraic y=x^2+3x-29 y=2x-9

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

7 0

Step-by-step explanation:

Given equations:

y = x² + 3x - 29 ------ (i)

y = 2x - 9 ---------------- (ii)

Now to solve this problem, we must determine the value of x and y;

Equate equations 1 and 2;

x² + 3x - 29 = 2x - 9

x² + 3x - 2x - 29 + 9 = 0

x² + x - 20 = 0

x² + 5x - 4x - 20 = 0

x(x + 5 ) - 4(x + 5) = 0

(x - 4) (x+ 5) = 0

x - 4 = 0 or x + 5 = 0

x = 4 or x = -5;

So; solve for y now;

y = 2x - 9

input x = 4 or x = -5;

y = 2(4) - 9 or y = 2(-5) - 9

y = -1 or y = -19

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