Question

Y=x^2-3x-6x+y=2Help 50 Points!!! Show Work

Answer 1

X + y = 2 —> y = 2 - x
insert to first equation
2-x=x^2-3x-6
x^2 - 3x - 6 - 2 + x = 0
x^2 - 2x - 8 = 0
(x-4)(x+2) = 0
x = 4 or x = -2

Answer 2

Answer:

x=-2 and y=4 or x=4 and y=-2

Step-by-step explanation:

put the value for y (first equation) in for the y in the second equation so it is x+x^2-3x-6=2

simplify

x^2-2x-8=0

factor and you get (x-4)(x+2)=0

(x-4)=0.      x=4

x+2=0        x=-2

now insert that back into x+y=2

and you get

y=-2

y=4

respecitvely

Hope this helps :)