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2 years ago

Y=x^2-3x-6x+y=2Help 50 Points!!! Show Work

2 answers:

5 0

X + y = 2 —> y = 2 - x
insert to first equation
2-x=x^2-3x-6
x^2 - 3x - 6 - 2 + x = 0
x^2 - 2x - 8 = 0
(x-4)(x+2) = 0
x = 4 or x = -2

Zigmanuir [339]2 years ago

4 0

Answer:

x=-2 and y=4 or x=4 and y=-2

Step-by-step explanation:

put the value for y (first equation) in for the y in the second equation so it is x+x^2-3x-6=2

simplify

x^2-2x-8=0

factor and you get (x-4)(x+2)=0

(x-4)=0. x=4

x+2=0 x=-2

now insert that back into x+y=2

and you get

y=-2

y=4

respecitvely

Hope this helps :)

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2 years ago

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Answer:

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Step-by-step explanation:

We are given that the ages of two brothers have a ratio of 2 to 1. When 4 years have passed, the ratio of their ages will be 8 to 6.

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$\frac{x}{y} =\frac{2}{1}$

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