Answer:
The distance between B and lighthouse is 3.8688 km
Step-by-step explanation:
Given:
The angle made from ship to lighthouse is 36.5 degrees
and that of point B is 73 degrees.
To Find:
Distance Between Point B and Lighthouse
Solution:
<em>Consider a triangle LAB(Refer the attachment )</em>
And Point C is on the line AB as A i.e. ship is sailing to B
So C is at 5 km from A.
Now In triangle LAC,
Using Trigonometry Functions as ,
tan(36.5)=LC/AC
LC=tan(36.5)*AC
=0.7399*5
=3.6998 km
Now In triangle LBC,
As,
Sin(73)=LC/LB
LB=LC/(Sin(73))
=3.6998/0.9563
=3.8688 km
LB=3.8688 km
4tan^(2)x-((4)/(cotx))+sinxcscx
Multiply -1 by the (4)/(cotx) inside the parentheses.
4tan^(2)x-(4)/(cotx)+sinxcscx
To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions.
4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin...
Complete the multiplication to produce a denominator of cotx in each expression.
(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot...
Combine the numerators of all expressions that have common denominators.
<span>
(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
Answer:
Step-by-step explanation:
Sign. We will get a positive number. So a positive divided by positive is positive and a negative divided by a negative is also positive. Now if the two numbers have different signs.
Answer:
A= 14 B=17 C=20 D=26
Step-by-step explanation:
Not 100% sure this is what you needed but this is my try.
The awnser is 145
(50 divided 2) = 25
5 to the power of 3= 125
-5
=145
