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3 years ago

Mr. Howard planted a new garden. The garden is 15 feet long and 4 feet wide. What is the perimeter of mr. Howard's garden?

Mathematics

1 answer:

MrRissso [65]3 years ago

7 0

Answer: 38 feet

Step-by-step explanation:

Based on the dimensions of the garden, we can infer that it a rectangular garden because one side is longer than the other.

The perimeter of a rectangle is calculated as:

= (2 * length) + (2 * width)

= (2 * 15) + (2 * 4)

= 30 + 8

= 38 feet

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(a) Margin of error ( E) = $2,000 , n = 54

(b) Margin of error ( E) = $1,000 , n = 216

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Step-by-step explanation:

Given -

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$E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}$

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(b) Margin of error ( E) = $1,000

E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

1000 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}$

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E = $Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}$

500 = $Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}$

Squaring both side

$500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}$

$n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}$

n = 864

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