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Elina [12.6K]
3 years ago
11

A ball falling from a building has a kinetic energy of 2000 J and potential energy of 2376 J. What is the mechanical energy of t

he ball?
A. 376 J
B. 1.188 J
C. 4376 J
D. 4.75x106 J
Physics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

C. 4736J

Explanation:

The mechanical energy of ball is the sum of its kinetic energy and potential energy at any point;

 Mechanical energy  = kinetic energy + potential energy

Given:

kinetic energy  = 2000J

potential energy  = 2376J

So;

 Mechanical energy  = 2000J + 2376J  = 4736J

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Responder:

12374550,527 N / m²

Explicación:

Dado que:

Número de tacos = 10

Área de cada montante = 0.01 in²

Peso total de la persona = 180 libras

Usando la relación:

Presión = Fuerza / Área

La fuerza ejercida es el producto de la masa y la aceleración debido a la gravedad.

Masa = 180 libras = 81,47 kg

Aceleración por gravedad = 9,8 m / s²

Área total = (número de montantes * Área por montante) = (10 * 0.01) = 0.1 pulg²

Conversión a m²:

0,1 pulg² = 6,452 * 10 ^ -5 m²

Por lo tanto,

Presión = (81,47 * 9,8) / (6,452 * 10 ^ -5)

Presión = 798.406 / 0.00006452

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3 years ago
Which of the following statements is consistent with Thomson’s and Millikan’s work with cathode rays and electrons? (A) Cathode
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Answer:

Dalton's ideas proved foundational to modern atomic theory. However, one of his underlying assumptions was later shown to be incorrect. Dalton thought that atoms were the smallest units of matter-−minustiny, hard spheres that could not be broken down any further. This assumption persisted until experiments in physics showed that the atom was composed of even smaller particles. In this article, we will discuss some of the key experiments that led to the discovery of the electron and the nucleus.

J.J. Thomson and the discovery of the electron

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19, start superscript, start text, t, h, end text, end superscript century, physicist J.J. Thomson began experimenting with cathode ray tubes. Cathode ray tubes are sealed glass tubes from which most of the air has been evacuated. A high voltage is applied across two electrodes at one end of the tube, which causes a beam of particles to flow from the cathode (the negatively-charged electrode) to the anode (the positively-charged electrode). The tubes are called cathode ray tubes because the particle beam or "cathode ray" originates at the cathode. The ray can be detected by painting a material known as phosphors onto the far end of the tube beyond the anode. The phosphors spark, or emit light, when impacted by the cathode ray.

A diagram of a cathode ray tube.

A diagram of a cathode ray tube.

A diagram of J.J. Thomson's cathode ray tube. The ray originates at the cathode and passes through a slit in the anode. The cathode ray is deflected away from the negatively-charged electric plate, and towards the positively-charged electric plate. The amount by which the ray was deflected by a magnetic field helped Thomson determine the mass-to-charge ratio of the particles. Image from Openstax, CC BY 4.0.

To test the properties of the particles, Thomson placed two oppositely-charged electric plates around the cathode ray. The cathode ray was deflected away from the negatively-charged electric plate and towards the positively-charged plate. This indicated that the cathode ray was composed of negatively-charged particles.

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Explanation:

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3 years ago
A Ferris wheel turns at a constant 150.0 revolutions per hour. (a) Express this rate of rotation in units of radians per second.
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Answer:

(a) 0.261 rad/s

(b) 1007.72 m

Explanation:

The angular velocity of the Ferris wheel is 150.0 revolutions per hour.

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1 hour = 3600 seconds

1 revolution = 2π radians

You use the previous conversion factors:

150.0\ \frac{rev}{h}*\frac{2\pi \ rad}{1\ rev}*\frac{1\ h}{3600\ s}=0.261\frac{rad}{s}

In units of radians per seconds the wheel turns at 0.261 rad/s

(b) To find the arc length described by the wheel, you first calculate the angle described by the  wheel in the time t, by using the following formula:

\theta=\omega t     (1)

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t: time = 4.95 min

You first convert the time to units of seconds

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Next, you replace the values of the parameters in the equation (1):

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Next, you use the following formula for the arc length:

s=r\theta     (2)

r: radius of the wheel = 13.0 m

You replace the values of the parameters in the equation (2):

s=(13.0m)(77.51rad)=1007.72m

The arc length described by the wheel is 1007.72m

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