The diagram shows a positive charge moving in a magnetic field. a field of circles labeled b. there is a positively charged part
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Answer:
Explanation:what’s the answer ?
Answer:
(a) Charge density σ=6.6375×10²nC/m²
(b) Total charge Q=1.47×10²nC
Explanation:
Given Data
A=47.0 cm =0.47 m
Electric field E=75.0 kN/C
To find
(a) Charge density σ
(b)Total Charge Q
Solution
For (a) charge density σ
From Gauss Law we know that
Φ=Q/ε₀.......eq(i)
Where
Φ is electric flux
Q is charge
ε₀ is permittivity of space
And from the definition of flux
Φ = EA
The flux is electric field passing perpendicularly through the surface
Put the this Φ in equation(i)
EA =Q/ε₀
where Q(charge)=σA
EA=(σA)/ε₀
E=σ/ε₀
σ=ε₀E
σ=6.6375×10²nC/m²
For (b) total charge Q
Q=σA
We have centripetal acceleration =
So, v =
Now by equation of motion we have S= ut +0.5a
S =displacement, u = initial velocity, a= acceleration and t = time
Here S = 2r and a = g , u = 0
Distance traveled in horizontal direction =