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3 years ago

Net force f causes mass m1 to accelerate at rate

2 answers:

6 0

Well, if F = ma, then to find the mass the equation is m = Fa

So then m(1) = Fa(1)
m(2) = F(3)a(2)

Fa(1):F(3)a(2) should be the ratio, though the question doesn’t clarify how simplified this answer needs to be. So it may be incorrect.

Genrish500 [490]3 years ago

4 0

Answer:

1:1.5

Explanation:

Net force f causes mass m1 to accelerate at rate

a. a net force of 3f causes mass m2 to accelerate at rate 2a. what is the ratio of mass m1 to mass m2?

force is that which changes a body's state of rest or uniform motion in a straight line

mass is the quantity of matter in a body

acceleration is cane in velocity per time

form newtons second law of motion, we know tat te rate of cane in momentum is directly proportional to te force applied

f=km(v-u)/t.

k=1

(v-u)/t.=a

f=ma

for the first case

f=m1a

m1=f/a

for the second case

3f=m2*2a

m2=3f/2a

equating the first case with the second case

f/a=1.5f/a

1:1.5

the ratio of mass m1 to mass m2

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3 years ago

Suppose a distant world with surface gravity of 5.20 m/s2 has an atmospheric pressure of 7.16 ✕ 104 Pa at the surface. (a) What

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Answer:

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Explanation:

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3 years ago

You are trying to determine the specific gravity of a solid object that floats in water. If m is the mass of your object, mS is

Alisiya [41]

Answer:

Specific Gravity = m/[m(s)-m(os)]

Explanation:

Specific gravity, also called relative density, is the ratio of the density of a substance to the density of a reference substance. By this definition we need to find out the ratio of density of the object of mass m to the density of the surrounding liquid.

m = mass of the object

Weight in air

W (air) = mg, where g is the gravitational acceleration

Weight with submerged with only one mass

m(s)g + Fb = mg + m(b)g, consider this to be equation 1

where Fb is the buoyancy force

Weight with submerged with both masses

m(os)g + Fb’ = mg + m(b)g, consider this to be equation 2

equation 1 – equation 2 would give us

m(s)g – m(os)g = Fb’ – Fb

where Fb = D x V x g, where D is the density of the liquid the object is submerged in, g is the force of gravity and V is the submerged volume of the object

m(s)g – m(os)g = D(l) x V x g

m(s) – m(os) = D(l) x V

we know that Mass = Density x V, which in our case would be, D(b) x V, which also means

V = Mass/D(b), where D(b) is the density of the mass

Substituting V into the above equation we get

m(s) – m(os) = [D(l) x m)/ D(b)]

Rearranging to get the ratio of density of object to the density of liquid

D(b)/D(l) = m/[m(s)-m(os)], where D(b)/D(l) denotes the specific gravity

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3 years ago

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OLEGan [10]

Answer:

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