Explanation:
Let the speed of jet be j and speed of wind be w.
Flying against the wind a jet travels 1710 miles in 3 hours
Distance = 1710 miles
Time = 3 hours
We have
Distance = Speed x Time
1710 = Speed x 3
j - w = 570 miles per hour ----------------eqn 1
Flying with the wind the same jet travels 6230 miles in 7 hours
Distance = 6230 miles
Time = 7 hours
6230 = Speed x 7
j + w = 890 miles per hour ----------------eqn 2
eqn 1 + eqn 2
2 j = 1460
j = 730 mph
Substituting in eqn 2
730 + w = 890
w = 160 mph
Speed of jet is 730 miles per hour and speed of wind is 160 miles per hour.
Answer:
11.47 m high
All of the Kinetic Energy converts to Potential energy
1/2 m v^2 = mgh divide both sides by 'm'
1/2 v^2 = gh (note that the masses given are irrelevant !)
(1/2 v^2) / g = h
(1/2 (15^2) / 9.81 = h = 11.47 m
The final velocity is v =-0.2m/s , v = -3.2 m/s
Given data,
Mass of glider A (M) = 0.15 kg
Mass of glider B (M) = 0.3 kg
Initial velocity of A (u) = 0.80ms-1
Initial velocity of B ( u) = -2.2m/s
Momentum and kinetic energy are conserved in elastic collision . So,
Mu+Mu = Mv+Mv
0.15×0.8+0.3x(-2.2) = 0.15v+0.3v
-0.54 = 0.15v+0.3v
Again if,
u+v =u+v
0.8 +v =-2.2+v
v-v = -3
Solving for -0.54 = 0.15v+0.3v and v-v = -3 , we get
v =-0.2m/s , v = -3.2 m/s
Therefore,The final velocity is v =-0.2m/s , v = -3.2 m/s
Learn more about velocity here:
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1.5mi/hr, 4.5mi/hr
Given:
45 min = 0.75h, 15 min = 0.25h
(1) 0.75v₁ = 0.25v₂
(2) v₁ = v₂ - 3
Solve for v₁ and v₂:
0.75(v₂ - 3) = 0.25v₂ = 0.75v₂ - 2.25 = 0.25v₂
0.5v₂ = 2.25
v₂ = 4.5
v₁ = 1.5