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gizmo_the_mogwai [7]
3 years ago
15

Lmkk if u know this, i need sum help

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

use cos to get an equation and then solve.

You might be interested in
Which equation of a line passes through the points (3, −1) and (6, 1)?
Vaselesa [24]

Answer:

Y = 2/3x - 3

Step-by-step explanation:

Recall the general equation for a straight line is

y = mx + b

where m is the gradient and b is the y-intercept

given 2 points whose coordinates are (x1, y1) and (x2, y2), m can be found with the following formula:

m = \frac{y1-y2}{x1-x2}

in this case, x1 = 3, y1 = -1, x2 = 6, y2=1

applying these values to the formula for m will give

m =  (-1 -1) / (3-6) = 2/3

We can see immediately that only the first (top-most) answer has this value for m and we can guess that this is probably the answer.

But we can still check to confirm:

If we substitute this back into the general equation, we get:

y = (2/3)x + b

In order to find the value for b, we substitute any one of the 2 given points back into this equation. Lets choose (6,1)

1 = (2/3)(6) + b

1 = 4 + b

b = -3

Confirm  Y = 2/3x - 3 is the answer.

4 0
3 years ago
What is the perimeter of the figure? <br><br> A. 144 cm <br> B. 76 cm <br> C. 74 cm <br> D. 45 cm
tatiyna
76 cm would be your answer, so B.
8 0
3 years ago
Read 2 more answers
If John ran a 5-kilometer marathon, how long was that in meters? A. 500 m B. 1000 m C. 5,000 m D. 50,000 m
Karolina [17]
The answer is c- 5,000
7 0
3 years ago
Read 2 more answers
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

8 0
1 year ago
I need help with this asap
dedylja [7]

I got no solution i might be wrong tho

4 0
2 years ago
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