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Delvig [45]
3 years ago
15

A 3rd3^{\text{rd}}3rd3, start superscript, start text, r, d, end text, end superscript degree binomial with a constant term of 8

888
Choose 1 answer:

Choose 1 answer:


(Choice A)

A

8x3+2x+38x^3+2x+38x3+2x+38, x, cubed, plus, 2, x, plus, 3

(Choice B)

B

2x8+32x^8+32x8+32, x, start superscript, 8, end superscript, plus, 3

(Choice C, Checked)

C

x3−x2+8x^3-x^2+8x3−x2+8x, cubed, minus, x, squared, plus, 8

(Choice D)

D

−5x3+8-5x^3+8−5x3+8minus, 5, x, cubed, plus, 8
Mathematics
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

-5x^3 + 8

Step-by-step explanation:

See comment for complete question

Given

Degree \to 3rd

Constant \to 8

Type \to Binomial

Required

Which of the options is true

Type \to Binomial

This implies that the polynomial has just 2 terms

The above shows that (a), (b) and (c) are not true because they have more than 2 terms

Degree \to 3rd

This implies that the highest power of x is 3

Constant \to 8

The second term of the polynomial must be +8

Only (d) satisfy the above conditions

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