Answer:
Step-by-step explanation:
Complementary angles sum up to .
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A 3rd3^{\text{rd}}3rd3, start superscript, start text, r, d, end text, end superscript degree binomial with a constant term of 8
1 answer:
Answer:
Step-by-step explanation:
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Given
Required
Which of the options is true
This implies that the polynomial has just 2 terms
The above shows that (a), (b) and (c) are not true because they have more than 2 terms
This implies that the highest power of x is 3
The second term of the polynomial must be +8
Only (d) satisfy the above conditions
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Answer:
The reason is because linear functions always have real solutions while some quadratic functions have only imaginary solutions
Step-by-step explanation:
An asymptote of a curve (function) is the line to which the curve is converging or to which the curve to line distance decreases progressively towards zero as the x and y coordinates of points on the line approaches infinity such that the line and its asymptote do not meet.
The reciprocals of linear function f(x) are the number 1 divided by function that is 1/f(x) such that there always exist a value of x for which the function f(x) which is the denominator of the reciprocal equals zero (f(x) = 0) and the value of the reciprocal of the function at that point (y' = 1/(f(x)=0) = 1/0 = ∞) is infinity.
Therefore, because a linear function always has a real solution there always exist a value of x for which the reciprocal of a linear function approaches infinity that is have a vertical asymptote.
However a quadratic function does not always have a real solution as from the general formula of solving quadratic equations, which are put in the form, a·x² + b·x + c = 0 is , and when 4·a·c > b² we have;
b² - 4·a·c < 0 = -ve value hence;
√(-ve value) = Imaginary number
Hence the reciprocal of the quadratic function f(x) = a·x² + b·x + c = 0, where 4·a·c > b² does not have a real solution when the function is equal to zero hence the reciprocal of the quadratic function which is 1/(a·x² + b·x + c = 0) has imaginary values, and therefore does not have vertical asymptotes.