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Ilia_Sergeevich [38]
3 years ago
12

Drag the green point on the tape diagram to model a discount of 27%.

Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

73%

Step-by-step explanation:

Let us have the original price as $100

A discount of 27% will be;

27/100 * 100 = $27

so, the value to be paid will be $100 - $27 = $73

Now, what percentage of $100 is the $73 that was paid

that would be;

73/100 * 100% = 73%

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(x² + 16)(x² - 16)
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The area of a right triangle is 210 square inches. The height of the right triangle is 35 inches.
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One thousand independent rolls of a fair die will be made. Compute an approximation to the probability that the number 6 will ap
pashok25 [27]

Answer:

0.19

Step-by-step explanation:

We are given that

Number of rolls of die=n=1000

Let the event of six coming up be success.Then, in each trial , the probability of success =p=P(success)=P(6)=\frac{1}{6}

Let X be the random variable  for the number of sixes  in the 1000 rolls of die.

Then, X\sim Binom(1000,\frac{1}{6})

Since, n is very large,the binomial random variable can be approximated as normal random variable.

Mean,\mu=np=1000\times \frac{1}{6}=166.67

Variance=\sigma^2=np(1-p)=1000\times \farc{1}{6}\times (1-\frac{1}{6})=1000\times \frac{5}{36}=138.89

X\sim N(166.67,138.89)

P(150\leq X\leq 200)=P[\frac{150-166.67}{11.79}\leq \frac{X-\mu}{\sigma}\leq \frac{200-166.67}{11.79}]

=P[-1.41\leq Z\leq 2.83]=P[Z\leq 2.83]-P[Z

=\phi(2.83)-\phi(-1.41)

=0.9977-0.0793=0.9184

Thus, the probability that the number 6 appears between 150 to 200 times=0.92

Now, given that 6 appears exactly 200 times .

Therefore, other number appear in other 800 rolls .

We have to find the probability that the  number 5 will appear less than 150 times.

Therefore, for 800 rolls, let the event of 5 coming up be success.

Then , p=P(success)=P(5)=\frac{1}{5}

Let Y be the random variable denoting the number of times  5 coming up in 800 rolls.

Then, Y\sim bin(800,\frac{1}{5})

Mean,\mu=np=800\times \frac{1}{5}=160

Variance, \sigma^2=np(1-p)=800\times \frac{1}{5}(1-\frac{1}{5})=128

Y\sim N(160,128) because n is large

P(Y

P(Y

Hence, the probability that the number 5 will appear less than 150 times given that 6 appeared exactly 200 times=0.19

4 0
3 years ago
Quiz 3<br> Apply the distributive property to create an equivalent expression.1/2(6e-3f-3/4)
liraira [26]

Answer:

Distribute 1/2 to all of the terms inside the parenthesis and you will get: 3e - 3/2f - 3/8

3 0
3 years ago
For the graph below, which of the following is a possible function for f?
netineya [11]

Answer:

The function f is perhaps a function of the form f(x) = a^{r\cdot x}, \forall \,x\in \mathbb{R}.

Step-by-step explanation:

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f(x) = a^{r\cdot x}, \forall \,x\in \mathbb{R}

The function f is perhaps a function of the form f(x) = a^{r\cdot x}, \forall \,x\in \mathbb{R}.

5 0
3 years ago
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