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kirza4 [7]
2 years ago
6

A receptionist earned $443 a week last year. What was her yearly salary

Mathematics
2 answers:
Sindrei [870]2 years ago
5 0
Yearly salary =  $443*52 = $23,036
Maru [420]2 years ago
4 0
$23,036 , If you multiply the weekly amount ($443 ) by the amount of weeks (52) in a year you receive $23,036 in a yearly salary
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Can someone help me with this question please! <br> 5-x=12
alisha [4.7K]

Answer:

x=-7

Step-by-step explanation:

Subtract 5 from both sides.

−x=12−5

Subtract 5 from 12 to get 7.

−x=7

Multiply both sides by −1.

x=−7

3 0
3 years ago
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The N71-90 virus will give an infected person a mild rash on their arms once the person has 1 billion of the virus cells in thei
Naya [18.7K]

Answer:

  • B. 256

Step-by-step explanation:

<u>Given function:</u>

  • v(h) = 2^(h/4)

<u>It can be rewritten as:</u>

  • v(d) = 2^d, where d- number of divisions

<u>If number of divisions is 8, then:</u>

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2 years ago
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Type the simple subject of this sentence.the plane leaves at 6:16 and arrives at 10:50.
Jet001 [13]
Shouldn't this be in the language section? But okay. I would say the simple subject would be "plane"

5 0
2 years ago
Solve the following equation by factoring:9x^2-3x-2=0
olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}

Step-by-step explanation:

Original quadratic equation is 9x^{2}-3x-2=0

Divide both sides by 9:

x^{2} - \frac{x}{3} - \frac{2}{9}=0

Add \frac{2}{9} to both sides to get rid of the constant on the LHS

x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}  ==> x^{2} - \frac{x}{3}=\frac{2}{9}

Add \frac{1}{36}  to both sides

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}

This simplifies to

x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = \frac{1}{6}\right) we can see that

\left(x - \frac{1}{6}\right)^2 = x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}

So

\left(x - \frac{1}{6}\right)^2=\frac{1}{4}

Taking square roots on both sides

\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}

So the two roots or solutions of the equation are

x - \frac{1}{6}=-\sqrt{\frac{1}{4}}  and x - \frac{1}{6}=\sqrt{\frac{1}{4}}

\sqrt{\frac{1}{4}} = \frac{1}{2}

So the two roots are

x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}

and

x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}

7 0
1 year ago
Given the equation x + 2y = 0, which equation will form a system of linear equations without a solution?
Oxana [17]

Answer:

2.5 and -0.75

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3 years ago
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