Find the number of units in the length of diagonal $DA$ of the regular hexagon shown. Express your answer in simplest radical fo
1 answer:
17.32 the number of units in the length of diagonal $DA$ of the regular hexagon.
<h3>How do you find the length of the diagonal of a regular hexagon?</h3>Six equilateral triangles can be formed from the hexagon. The equilateral triangle has an equal length on each side. The diagonal of the hexagon is formed by joining two of the sum of the lengths of the equilateral triangles. As a result, the hexagon's diagonal is twice as long as its sides.
For a polygon, the SUM of the internal angles is:
(n-2) * 180 (n=6 for hexagon)
(6-2)*180 = 720 Thus EACH angle is : 720/6 = 120 degrees
Therefore, the triangle's main angle is 120 degrees, and its other two angles are equal.
There are 180 degrees in any triangle:
(180-120) / 2 = 30 degrees for each of the smaller angles.
Now use the law of sines:
10/sin30 = x/(sin120)
10/(.5) × (sqrt3 )/ 2 = x
10 sqrt 3
10/sin30 × sin 120 = 17.32
17.32 is the number of units in the length of diagonal $DA$ of the regular hexagon.
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Answer:
The length of PQ is <u>18</u> feet.
The length of PR is <u>18</u> feet.
The length of QR is <u>24</u> feet.
Step-by-step explanation:
A way to set an equation up for this problem is:
where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.
Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:
Don’t solve the whole equation, just solve the part of the equation, which is equal to 24. So the final equation is this:
Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).
Sorry for the long explanation.
But hope this helps and answers your question :)