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Nana76 [90]
2 years ago
9

Who helped / guide you in answer your module?​

Mathematics
1 answer:
Svet_ta [14]2 years ago
3 0
Please explain more and I would answer!!!
You might be interested in
Which of the following relations is a function? A.{ (-2, 4), (-1, 3), (5, 2), (1, 4) } B.{ (1, 7), (1, 8), (2, 7), (3, 8) } C.{
siniylev [52]
From the pairs of x,y, if the set has two "x" of the same value, that is, "x" repeats, or an x-repeat, then is NOT a function

so, the group that doesn't have any x-repeats, is a function, now let's check

\bf A.\{ (-2, 4), (-1, 3), (5, 2), (1, 4) \}\\\\
B.\{ (\boxed{1}, 7), (\boxed{1}, 8), (2, 7), (3, 8) \}\impliedby \textit{has one re}\textit{peat, no dice}\\\\
C.\{ (2, 4), (\boxed{4}, 6), (\boxed{4}, 8), (6, 4) \}\impliedby \textit{also has one re}\textit{peat, no dice}\\\\
D.\{ (\boxed{5}, 7), (6, 3), (8, 6), (\boxed{5}, 4) \}\impliedby \textit{same, has one re}\textit{peat, no dice}
3 0
3 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
3 years ago
Plllllllllllllllllleassssssssseeeeeeeeee help
Vlad1618 [11]

Answer:

1/(5^12 * 32^3 * 9^15)

Step-by-step explanation:

5^-12 = 1/(5^12)

32^-3 = 1/(32^3)

9^-15 = 1/(9^15)

1/(5^12) * 1/(32^3) * 1/(9^15) = 1/(5^12 * 32^3 * 9^15)

8 0
3 years ago
What is 2700 divided 90​
crimeas [40]

Answer:

30

Step-by-step explanation:

2700/90 = 30

27/9 = 3

100/10 = 10

3*10 = 30

8 0
2 years ago
Does any one know how to do this. It would be such a life saver if you could help me out. Thx
Aneli [31]

Answer:

1: (3 ,- 4)

2:up (a > o)

3: -4

4: 2 units to the right

5: 4 units down

6: y = (x-2)^2-4

7:

8:

9: (5,9)

10: x=5

11: (4,7) and (6,7)

12:

Step-by-step explanation:

I'm not sure if you wanted it explained or answered , so i just answered most of them. Sorry if you wanted it explained.

3 0
2 years ago
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