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Nana76 [90]
3 years ago
9

Who helped / guide you in answer your module?​

Mathematics
1 answer:
Svet_ta [14]3 years ago
3 0
Please explain more and I would answer!!!
You might be interested in
I NEED HELP I WILL GIVE BRAINLEST!!!!!!!!!!!
WARRIOR [948]
The answer is 81 because if we plug in 9:

9^2  * 9^0

We know that anything to the zero power is one, so we are left with

9^2 which equals 81
8 0
3 years ago
Darnell buys homes and flips them by completing renovations to turn a profit on his investment. He is currently working on a hou
ipn [44]

Answer:

Look below for answer! Have a great day and please mark me brainliest!

Step-by-step explanation:

Bedroom 1: 22x15=330

330x7.25=2392.5

Bedroom 2: 15x12=180

180x7.25=1305

Bedroom 3: 13x12=156

156x7.25=1131

2392.5+1305+1131= 4828.5

Bedroom 1:  22x15=330

330x6.75=2227.5

Bedroom 2: 15x12=180

180x6.75=1215

Bedroom 3: 13x12=156

156x6.75=1053

2227.5+1215+1053+100= 4595.5

Therefore, 6.75 per square foot plus a $100 fixed installation fee would be the cheapest.

4 0
3 years ago
Simplify 2/√5
Arada [10]
The answer would be 2√5/5

As a rule, you cannot have any radical as a denominator. That's why you gotta multiply √5 with √5 which would be √25. The square root of this is 5, and now you have disposed of the radical! Hurray. However, keep in mind, that when you multiply √5, you also multiply it to the numerator. So, yeah, after this, you get the answer.

Hopefully, my explanation makes sense. :)
4 0
3 years ago
HELPPPPP!!! ASAPPPP!!!!!!
Natali [406]
3. You add more gas to your car and the cost increases
8 0
3 years ago
Find an equation of the plane passing through (0 comma negative 1 comma 1 )that is orthogonal to the planes 3xplus4ynegative 3ze
galben [10]

Answer:

The equation of plane is

22x -3y+18z = 21

Step-by-step explanation:

We have to find the equation of plane passing through the point (0,-1,1) and orthogonal to the planes

n_1:3x + 4y-3z = 0\\n_2:-3x + 2y + 4z = 5

Thus, we can write:

n_1:\\n_2:

We will evaluate:

n = n_1\times n_2\\\\n = \left[\begin{array}{ccc}i&j&k\\3&4&-3\\-3&2&4\end{array}\right] \\\\n = i(16 + 6)-j(12-9) +k(6+12)\\n = 22i-3j+18k\\n =

The required plane passes through the point (0,-1,1)

Thus, the equation of plane is

n.=0\\\Rightarrow .=0\\\Rightarrow 22(x) -3(y+1) + 18(z-1) =0\\\Rightarrow 22x - 3y - 3 + 18z - 18 = 0\\\Rightarrow 22x -3y+18z = 21

is the required equation of the plane.

7 0
3 years ago
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