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ahrayia [7]
3 years ago
14

6. 12(30-12) 3 helpppp

Mathematics
2 answers:
satela [25.4K]3 years ago
7 0

Answer:

216

Step-by-step explanation:30-12=18 so 18 x 12=216 hope that helped

NemiM [27]3 years ago
3 0

Answer:

648 is your answer

Step-by-step explanation:

hope this helps!!

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Solve for Y........................
aivan3 [116]
11 squared is 121
20 squared is 400
121+400= 521
The approximate square root of 521 is approximately 22.8254
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3 years ago
The area of a circle A is 85π ft2. ∠BAC is a central angle of the circle, and m∠BAC = 36°
BlackZzzverrR [31]
As stated the area of the circle is 85π ft2. The area of the sector BAC is a portion of this full circle area. the sector is made of 2 radii and arc that has rotated by 36°.
the magnitude of the central angle in the circle is 360°
Area for 360° central angle -  85π ft2
then the area for 1°            =  85π ft2/360°
the area of 36° sector         =  85π ft2/360° x 36°
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7 0
3 years ago
Rewrite as a simplified fraction.
n200080 [17]
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4 0
3 years ago
How many tens are in 1290
lozanna [386]

Answer:

129

Step-by-step explanation:

Divide 1290 by 10 and you get 129

3 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through (-6,0) and is parallel to the line y=5x-43
AVprozaik [17]

The equation of the line that passes through (-6,0) and is parallel to the line y = 5x - 43 in slope intercept is y = 5x + 30

<em><u>Solution:</u></em>

Given that line that passes through (-6, 0) and is parallel to the line y = 5x - 43

We have to find the equation of line

Let us first find slope of line having equation y = 5x - 43

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c  ------- eqn 1

Where "m" is the slope of line and "c" is the y - intercept

On comparing equation of line y = 5x - 43 with slope intercept form y = mx + c,

we get m = 5

Thus slope of given line is 5

We know that slopes of parallel lines are equal

Thus the slope of line parallel to given line is also 5

Now let us find equation of line having slope "5" and passes through (-6, 0)

Substitute m = 5 and (x, y) = (-6, 0) in eqn 1

y = mx + c

0 = 5(-6) + c

<h3>c = 30</h3>

<em><u>Thus the required equation is:</u></em>

Substitute c = 30 and m = 5 in eqn 1

y = 5x + 30

Thus the required equation of line is found

8 0
3 years ago
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