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Fudgin [204]
2 years ago
11

=

Mathematics
1 answer:
const2013 [10]2 years ago
4 0

The equation in the given standard form is (x+10)^2+(y+6)^2=5^2

<h3>Equation of a circle</h3>

The standard equation of a circle is expressed as:

(x-a)^2+(y-b)^2=r^2

Given the equation x^2 + y^2 + 20x + 12y + 111 =0

Group the function to have:

(x^2 +20x)+(y^2+ 12y) + 111 =0

Complete the squares to have:

(x^2 +20x)+(y^2+ 12y) + 111 =0\\(x^2+20x+10^2-10^2)+(y^2+12y+6^2-6^2)+111=0\\(x+10)^2+(y+6)^2 -100-36+111=0\\(x+10)^2+(y+6)^2-25=0\\(x+10)^2+(y+6)^2=25\\(x+10)^2+(y+6)^2=5^2

Hence the equation in the given standard form is (x+10)^2+(y+6)^2=5^2

Learn more on equation of a circle here: brainly.com/question/1506955

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3 years ago
Find the perimeter and area of the semi circle
OLga [1]

Answer:

Step-by-step explanation:

Perimeter of a semicircle with diameter d = πd/2 + d

5 0
3 years ago
Which of the following is the best approximation of the area of a circle whose diameter is 14 feet?
Ray Of Light [21]
Area of a circle is pi x r^2

R = d/2 = 14.2 = 7

Area = 3.14 x 7^2
Area = 3.14 x 49
Area = 153.86 round to 154

Answer is 154 square feet.
8 0
3 years ago
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
Three numbers have an average of 15. If two of the numbers are 10 and 12, then what is the other number?
AveGali [126]

Answer:

Step-by-step explanation:

(12+10+x)/3=15

15*3=12+10+x

45-12-20=x

X=23

3 0
2 years ago
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