9. ¹/₃(x + 6) = 8
¹/₃(x) + ¹/₃(6) = 8
¹/₃x + 2 = 8
<u> - 2 - 2</u>
3 · ¹/₃x = 6 · 3
x = 18
15. ¹/₅(x + 10) = 6
¹/₅(x) + ¹/₅(10) = 6
¹/₅x + 2 = 6
<u> - 2 - 2</u>
5 · ¹/₅x = 4 · 5
x = 20
20. ¹/₈(24x + 32) = 10
¹/₈(24x) + ¹/₈(32) = 10
3x + 4 = 10
<u> - 4 - 4</u>
<u>3x</u> = <u>6</u>
3 3
x = 2
32. 5 - ¹/₂(x - 6) = 4
5 - ¹/₂(x) - ¹/₂(-6) = 4
5 - ¹/₂x + 3 = 4
5 + 3 - ¹/₂x = 4
8 - ¹/₂x = 4
<u>- 8 - 8</u>
-2 · (-¹/₂x) = -4 · (-2)
x = 8
33. ²/₃(3x - 6) = 3
²/₃(3x) - ²/₃(6) = 3
2x - 4 = 3
<u> + 4 + 4</u>
<u>2x</u> = <u>7</u>
2 2
x = 3¹/₂
Answer:
n = - 
Step-by-step explanation:
Given
2nq = 3 + 7nq ( subtract 7nq from both sides )
- 5nq = 3 ( divide both sides by the multiplier - 5q )
n =
= - 
SIDE LENGTH OF TRIANGLE: 2.14 inches
SIDE LENGTH OF HEXAGON: 6 inches
To solve this problem, we know that the shapes have equal sides as it states “equilateral triangle”. A triangle has 3 sides and a hexagon has 6 sides. We are told the perimeters are the same so you can set their perimeters equal to each other to solve for x. You would get this : 3(1.4x + 2) = 6(0.5x +2)
With basic algebra you would get x= 5
Then you substitute that value into the length sides of the triangle and hexagon. For the triangle you would approx get 2.14 inches and for the hexagon 6 inches