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guajiro [1.7K]
1 year ago
13

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom

ials be both positive, negative, or one of each? Create an example to verify your claim.
Mathematics
1 answer:
gtnhenbr [62]1 year ago
5 0

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x +  8

Expand the equation

x^2 + 6x +  8 = x^2 + 4x + 2x +  8

Factorize the equation

x^2 + 6x +  8 = (x + 2)(x + 4)


Hence, the signs in the binomials should be both positive

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

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GarryVolchara [31]

Answer:

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natta225 [31]

Answer:

B

Step-by-step explanation:

To find the y-intercept, plug in x=0 in the original equation. (You want to find what y is when x=0)

2x + 3y = -12

2(0) + 3y = -12 (Plug in x=0)

3y = -12 (2*0=0, so you can ignore that part)

y = -4 (Divide both sides by 3)

This narrows down our choices to either A or B.


To find the x-intercept, plug in y=0 into the original equation. (You want to find what x is when y=0)

2x + 3y = -12

2x + 3(0) = -12 (Plug in y=0)

2x = -12 (3*0=0, so you can ignore that part)

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If our x intercept is -6 and our y intercept is -4, that makes our answer B.

4 0
3 years ago
Mm<br> E<br> 9. Solve: 3(x+4) ≤36<br> x&gt; 8<br> x≤8<br> x≤12<br> X&gt;12
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Step-by-step explanation:

3(x+4) ≤ 36

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1 year ago
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Step-by-step explanation:

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