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guajiro [1.7K]
2 years ago
13

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom

ials be both positive, negative, or one of each? Create an example to verify your claim.
Mathematics
1 answer:
gtnhenbr [62]2 years ago
5 0

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x +  8

Expand the equation

x^2 + 6x +  8 = x^2 + 4x + 2x +  8

Factorize the equation

x^2 + 6x +  8 = (x + 2)(x + 4)


Hence, the signs in the binomials should be both positive

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

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Write the decomposition that helps you, and then round to the given place value. Draw number lines to explain your thinking. Cir
egoroff_w [7]

Further explanation

There are general rules used in rounding numbers

1. Determine the rounded digit

2. Pay attention to the digits afterward (right). If the digit shows the numbers 0, 1, 2, 3 or 4, then the digit to be rounded is fixed, and the digit on the right is 0 all

3. If the digit on the right shows the numbers 5, 6, 7, 8 or 9, then the digit to be rounded is added to one, and the digit on the right side is made all 0

In rounding the nearest hundreds number, then we see the digit in the number tens (right of the digit hundreds), if it is worth 0, 1, 2, 3 or 4, then it remains, but if it shows numbers 5, 6, 7, 8 or 9, then the digit to be rounded is added one, and the right-hand side is 0

Calculated from the decimal point, the place on the right represents tents, hundredths, thousandths, etc.

a.  32.697

Decomposition

ten : 3

one : 2

tenth : 6

hundredth : 9

thousandths : 7

For the tenth number is 6, the value on the right is 9 then rounded become 32.7

For the hundredth number is 9, the value on the right is 7 then rounded become 32.70

for the one number is 2 , the value on the right is 6 then rounded become 33

b. 141.999

Decomposition

hundred : 1

ten : 4

one : 1

tenth : 9

hundredth : 9

thousandths : 9

a. For the tenth number is 9, the value on the right is 9 then rounded become 142.0

For the hundredth number is 9, the value on the right is 9 then rounded become 142.00

For the ten number is 4, the value on the right is 1 then rounded become

14

For the ten number is 1, the value on the right is 4 then rounded become

142

<h3>Learn more </h3>

five numbers that are round up and round down to 600

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all the numbers that round to 50

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round 4,398,202 to the nearest 100

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Round number 4278649 to nearest 100

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Keywords: round up, round down, the rounded digit

7 0
3 years ago
What number is 10 times as much as 50
Murljashka [212]

Answer:

500

Step-by-step explanation:

6 0
3 years ago
A NASA mathematician used a system of equations to determine the point in space where a satellite crossed paths with a massive p
nikitadnepr [17]

Answer:

Option D.

3 equations with 3 variables

Step-by-step explanation:

The coordinates of a point in space must necessarily have 3 components. One to describe the distance on the x axis, another to describe the distance on the y axis to the point, and a third to describe the distance on the z axis.

If we have three variables, then 3 equations are needed to solve the system. With less than 3 equations it would be impossible to solver the system.

Therefore the correct answer is option D.

3 equations with 3 variables

8 0
3 years ago
the average starting salary for this year's graduates at a large university (lu) is $55,000 with a standard deviation of $6,000.
alexira [117]

0.84% of the graduates will receive the tax break

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean  and standard deviation , the z-score of a measure X is given by:

Z = x - μ / σ

Z-scores are used to measure how far a measure is from the mean. We find the p-value associated with this Z-score by looking at the z-score table after finding the Z-score. The p-value represents the probability that the measure is smaller than X, which is the percentile of X. The probability of the measure being greater than X is calculated by subtracting 1 from the pvalue.

μ = $55,000 σ = $6,000

This is the pvalue of Z when X = $39,600. So

z = 39600 - 55000 / 6000

z = -2.5

z = -2.5 has a o value of 0.0084

0.84% of the graduates will receive the tax break.

To learn more about similar tax break:

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7 0
1 year ago
A new gas- and electric-powered hybrid car has recently hit the market. The distance traveled on 1 gallon of fuel is normally di
Doss [256]

Answer:

a) P [ Z > 70 ]  = 0.1075  or 10.75 %

b)  P [ Z < 60 ] = 0.1038   or  10.38 %

c)  P [ 55 ≤ Z ≤ 70 ] =  0.8882   or 88.82 %

Step-by-step explanation:

Normal Distribution  μ = 65    and σ = 4

a) The probability of the car travels more than 70 miles per gallon is:

P [ Z > 70 ]  =  (Z-μ) ÷ σ  ⇒   P [ Z > 70 ] = (70-65) ÷4     P [ Z > 70 ] = 1.25

the point 1.25 corresponds at values, from left tail up to 70 so we must go and look for the area for the point 1.24 which is 0.8925. Then we have the area or probability of all cars traveling up  to 70 miles therefore  we have to subtract 1 -0,8925

P [ Z > 70 ]  = 0.1075  or 10.75 %

b)The probability of the car travels less than 60 miles per gallon is:

P [ Z < 60 ]  = ( 60 - μ ) ÷  σ ⇒  P [ Z < 60 ] = (60-65)÷ 4    P [ Z < 60 ] = -1.25

Again -1.25 corresponds to 60 miles per gallon threfore we move to the left and find for point -1.26  which area is 0.1038 so

P [ Z < 60 ] = 0.1038     10.38 %

c) P [ 55 ≤ Z ≤ 70]

For  point  Z = 70 or 1.25 (case a above)  P [ Z ≤ 70] = (70-65)÷4  

P [ Z ≤ 70] = 1.25

In this case we got the whole area from the left tail up to 1.25

P [ Z ≤ 70]  = 0.8944 (includes the area of the point from the left tail up to the point assocciated to 55 miles and for that reason we have to subtract that area)

P [ Z ≥ 55 ]  = (55-65) ÷ 4     P [ Z ≥ 55 ] = -2.5  and the area is 0.0062

So P [ 55 ≤ Z ≤ 70 ] =  0.8944 - 0.0062  = 0.8882

8 0
4 years ago
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