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3 years ago

Out of these triangles which of them is a Right Triangle? 4, 6, 10 6, 8, 10 10, 24, 26

Mathematics

1 answer:

kupik [55]3 years ago

4 0

The answer for you is B.
6, 8, 10

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Two different families pay for entry into a water park.

icang [17]

Answer:

Adult ticket: $7

Child ticket: $2

Step-by-step explanation:

Set up a system of equations where a represents the cost of one adult ticket and c is the cost of one child ticket:

2a + 3c = 20

a + 4c = 15

Solve by elimination by multiplying the bottom equation by -2:

2a + 3c = 20

-2a -8c = -30

Add them together:

-5c = -10

c = 2

Now, we can plug in 2 as c to find the value of a:

2a + 3c = 20

2a + 3(2) = 20

2a + 6 = 20

2a = 14

a = 7

6 0

3 years ago

What is the value of x? (5 points)

Ahat [919]

I’m pretty sure the answer is 30!

3 0

3 years ago

Read 2 more answers

If the perimeter of the top of desk is 54 inches the length of the desk is

allsm [11]

Formula: $2width+2length=perimeter$

$length=15inches$

$width=?$

$Perimeter=54inches$

$2*15=30$ (There are two sides for the length)

$54-30=24$

$24/2=12$ (There are two sides for the width)

The width of the desk is 15 inches

----
-Geekhawk

4 0

3 years ago

An airplane pilot experiences weightlessness as she passes over the top of a loop-the-loop maneuver. if her speed is 200 m/s at

yulyashka [42]

Centripetal acceleration is given by:
g=v^2/r
where:
v=velocity
r=rate
But
V=200 m/s, g=9.8 m/s^2
plugging the values in the formula we obtain:
9.8=200^2/r
r=200^2/9.8
r=4081.63 m

5 0

3 years ago

On your wedding day you leave for the church 34 minutes before the ceremony is to begin, which should be plenty of time since th

Schach [20]

Answer:

Average speed is 37.35 mi/h

Step-by-step explanation:

given data

leave = 34 minutes before

church distance = 12.0 miles

average speed first 17 minutes = 5.0 mi/h

solution

so we find Total distance travel in first 17 minutes = speed × time

Total distance travel in first 17 minutes = 5 × $\frac{17}{60}$

Total distance travel in first 17 minutes = 1.416 mi

and

Distance Remaining = 12 - 1.416 = 10.584 mi

Time Remaining = 34 - 17 min = 17 min

remaining distance Average speed = $\frac{distance}{time}$

Average speed = $\frac{10.584}{\frac{17}{60}}$

Average speed is 37.35 mi/h

3 0

3 years ago