<h2><u>Question</u><u>:</u><u>-</u></h2>
A fruitseller bought 50kg of the fruits. He sold 30kg of fruits for the cost price of 35kg of fruits and he sold the remaining quantity for the cost Price of 18kg of fruits. calculate his profit or loss percent in the total transaction.
<h2><u>Answer</u><u>:</u><u>-</u></h2>
let the cost price be 50x
→he sells 30kg of fruits on it's CP of 35 kg
→CP of 30kg fruits = 30x
→SP of 35kg fruits = 35x
→remaing fruits are 20kg
→he sells 20kg of fruits on CP of 16kg
→CP of 20kg fruits = 20x
→SP of 20kg fruits = 16x
→total CP is = 50x
→total SP is = (35 + 16) = 51x
→SP > CP (it means profit)
→profit = SP-CP
→ 51-50
→ 1
<h2 /><h2><u>Now,</u></h2>
→ Profit% = gain/CP × 100
→ Profit% = 1/50 × 100
→ 2%
Hence the fruit seller had a profit% of 2%.
Answer:
Step-by-step explanation:
c+7
you have 7 more then a number c
Answer:
6 days <u>Please at least say thanks and leave a good review</u>
Step-by-step explanation:
1500 per week works 4 weeks
maximum would be 6000
if she is late 6 days she loses 900 dollars and would be left with 5100
if she is late 7 days she loses 1050 and would be left with 4950 so she can be late no more than 6 days
Answer:
=10
Step-by-step explanation:
because 20÷10=2
70÷10=7
50÷10=5
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Answer:
= x^3 + 15x^2 − 8x+7
Step-by-step explanation:
x^3 + 15x^2 − 8x + 7
There are no like terms.
Soo your answer will be: = x^3 + 15x^2 − 8x+7
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Hope I helped!!!
~Nuha
<3
<em>Δ new growth Δ</em>
