School A and B are competing in an academic contest. at the beginning of the final round, school A has 174 points and school B h
2 answers:
Answer:
School A gave 12 correct and 12 incorrect answers. School B gave 12 correct answers and the competition was tied.
Step-by-step explanation:
We are given the following information:
School A points = 174
School B points = 102
Every correct answer is awarded 10 points and every incorrect answer reduces 6 points.
Let x be the number of correct answer given by school A and thus x is the number of incorrect answer given by school A. The, school B also gives x number of correct answer.
Thus, the scored can be modeled with the following equations:
School A:
School B:
Since, both the schools tied, equating both the equations:
Thus, school A gave 12 correct and 12 incorrect answers. School B gave 12 correct answers and the competition was tied.
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<span>p(t)=-3t^2+18t-4
using a graphing tool, we can see the maximum of the graph
(see the attached figure)
A) </span><span>In what year of operation does Mr. Cash’s business show maximum profit?
</span>Mr. Cash’s business show maximum profit at year 3 (maximum in the parabole)
<span>B) What is the maximum profit?
23 (hundred of thousand of dollars) = 2.300.000 dollars
</span>c) What time will it be two late?
(This is the time when the graph crosses zero and the profits turn into losses )
5.77 years, or an estimate of about 69 months.