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Maksim231197 [3]
3 years ago
8

Help please ill give barinliest

Mathematics
2 answers:
lana66690 [7]3 years ago
4 0

Answer:

a

Step-by-step explanation:

ICE Princess25 [194]3 years ago
3 0

Answer:

A

Step-by-step explanation:

.

You might be interested in
Assume that P(E) = 0.471 and P(F) = 0.595. If E and F are independent, find P(E and F)
dsp73

The value of the probability P(E and F) is 0.2802

<h3>Independent probability</h3>

Events are known to be independent if the occurrence of one does not affect the other.

Given the following parameters

P (E) =0.471

P(F) = 0.595

If E and F are independent, then;

P(E and F) = P(E)P(F)

P(E and F)  = 0.471 * 0.595
P(E and F)  = 0.2802

Hence the value of the probability P(E and F) is 0.2802

Learn more on independent events here: brainly.com/question/1374659

#SPJ1

8 0
2 years ago
What does this equal? <br>-1/5p=-16
Vlad [161]
P=80 <---this is the answer
5 0
3 years ago
Because hit 7 more home runs than Beverly. Because hit 22 home runs. How many home runs did Beverly hit?
nekit [7.7K]
The answer choice isn't even up there. The answer is 15. Since Because hit 22 home runs; you would just subtract to find the number of Beverly's home runs since it says "7 more home runs than Beverly".


22 - 7= 15.

Hopefully this helps 



7 0
4 years ago
Read 2 more answers
HELP ASAP
Keith_Richards [23]
25/6=60/x

x=(60*6)/25
x=14.4sec
7 0
3 years ago
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
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