Answer:
y=2x+6 ; x+y=51
Step-by-step explanation:
assuming x is one number and y is the other -
one number (y) is 6 more (+6) than twice another (2x) -
using that knowledge we form an equation -
y=2x+6
the sum (x+y) is 51
using this knowledge we can make the equation -
x+y=51
now you have -
y=2x+6 or 2x-y=-6
x+y=51
using system of equations -
you add the equations -
3x=45
x=15
y=51-x => y=36
hope this helps!!
Ok so then line p is the equation y=x
is that all you needed?
Answer:
<em>f(x)=x²-3x-10</em>
Step-by-step explanation:
\begin{gathered}f(x) = x {}^{2} - 3x - 10 \\ to \: find \: x \: intercept \:o r \: zero \: substitute \: f(x) = 0\: \\ 0 = x {}^{2} - 3x - 10 \\ x {}^{2} - 3x - 10 = 0 \\ x {}^{2} + 2x - 5x - 10 = 0 \\ x(x + 2) - 5x - 10 = 0 \\ x(x + 2) - 5(x + 2) = 0 \\ (x + 2).(x - 5) = 0 \\ x + 2 = 0 \\ x - 5 = 0 \\ x = - 2 \\ x = 5\end{gathered}
f(x)=x
2
−3x−10
tofindxinterceptorzerosubstitutef(x)=0
0=x
2
−3x−10
x
2
−3x−10=0
x
2
+2x−5x−10=0
x(x+2)−5x−10=0
x(x+2)−5(x+2)=0
(x+2).(x−5)=0
x+2=0
x−5=0
x=−2
x=5
therefore the zeros of the equation are x₁=-2,x₂=5
48y + 40x factored is 8(6y+5x)
