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Inga [223]
2 years ago
12

FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions you have posted :) th

ank you very much!!! (22pts)

Mathematics
2 answers:
vitfil [10]2 years ago
6 0

Answer:

The answer is B : No Solution

lianna [129]2 years ago
6 0

Answer:

no solution

Step-by-step explanation:

x²-4 is (x+2)(x-2), which is your least common multiplier

So first, eliminate the denominators by multiplying all terms by (x+2)(x-2)

(x+2)(x-2)/(x-2) + (6x)(x+2)(x-2)/(x+2)(x-2) = 3(x+2)(x-2)/(x+2)

Then simplify

(x+2) + (6x) = 3(x-2)

combine the variables, and expand the right side of the equation

7x + 2 = 3x - 6

Subtract 2 from both sides

7x = 3x - 8

Substract 3x from both sides

4x = -8

Divide both sides by 4

x = -2

Although x = -2, the final answer is undefined.

Because if you plug x = -2 back into the equation, you would get...

for example, 3/(x+2) will become 3/(-2+2), which is 1/0

it is not possible to divide by 0

anything divided by 0 is undefined, therefore this equation has no solution.

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The ratio of the angles in a triangle is 3:10:7. what is the measure of the smallest angle?
STALIN [3.7K]
So add all of them and then see smallest one sorry if I'm wrong
3 0
3 years ago
NEED HELP WITH BOTH PLZ
Natalija [7]
For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
7 0
3 years ago
1
notka56 [123]
7 divided by 2 is 3.5 therefore the answer is:3.5
7 0
3 years ago
Janice is considering two restaurants for a party. The first restaurant charges $15 per person plus a flat rate of $175 to reser
yan [13]

Answer:

The answer is 15x + 175 = 9x + 329.

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
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