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2 years ago

BRAINIEST FOR CORRECT ANSWER Please solve these all for me i really need them

Mathematics

2 answers:

Ivahew [28]2 years ago

7 0

Answer:

9: 5y 10: 40x-4 11: 992a+5b 12: 24 list A: 24, 16, 21 list B 16, 24, 21

Step-by-step explanation:

I don’t have the rest but all of the problems are really easy

Scilla [17]2 years ago

4 0

Alright! What name is your book and what page?

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PLSSSS HELLLPPPPPPP How much would it cost to buy 3.4 pounds of Bartlett pears and 2.1 pounds of Concorde pears? Concorde pears

kirill [66]

Answer:

$13.10

Step-by-step explanation:

Concard $3.00 2.1 $6.30

Osband $3.00

Green Anjou $4.00

Bartlett $2.00 3.4 $6.80

Red Anjou $5.00

TOTAL = $13.10

5 0

3 years ago

Prove the identity with steps.

Sav [38]

Remember that a double angle formula for cosine is
$\cos(2x)=\cos^{2}x-\sin^{2}x$

So
$\cos^{2}(2x)-\sin^{2}(2x)=\cos(4x)$
$\rightarrow \cos^{2}(2x)-\sin^{2}(2x)=\cos(2*2x)$
$\rightarrow \cos^{2}(2x)-\sin^{2}(2x)=\cos^{2}(2x)-\sin^{2}(2x)$

4 0

2 years ago

Two circles have the same radius. Complete the description for whether the combined area of the two circles is the same as the a

Elodia [21]

Answer:

see below

Step-by-step explanation:

A = pi r^2

If they have the same radius they have the same area

A two circles = pi r^2 +pi r^2

= 2 pi r^2

If we double the radius

A = pi (2r)^2

= pi 4r^2

The combined area of two circles is 1/2 the area as the area of a circle with twice the radius.

5 0

3 years ago

Read 2 more answers

Put in order by least to greatest. 1,0.7,1/10

Finger [1]

Answer:

1/10, 0.7, 1

Step-by-step explanation:

1/10=0.1

0.7=7/10

1=1/1=1.0

3 0

3 years ago

Read 2 more answers

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

3 years ago