Answer:
3x^2 - 13x + 7
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
(((6•(x2))-5x)+3)-((3x2+8x)-4)
Step 2 :
Equation at the end of step 2 :
(((2•3x2) - 5x) + 3) - (3x2 + 8x - 4)
Step 3 :
Trying to factor by splitting the middle term
3.1 Factoring 3x2-13x+7
The first term is, 3x2 its coefficient is 3 .
The middle term is, -13x its coefficient is -13 .
The last term, "the constant", is +7
Step-1 : Multiply the coefficient of the first term by the constant 3 • 7 = 21
Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -13 .
-21 + -1 = -22
-7 + -3 = -10
-3 + -7 = -10
-1 + -21 = -22
1 + 21 = 22
3 + 7 = 10
7 + 3 = 10
21 + 1 = 22
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
3x2 - 13x + 7
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It is 6 over 5. 6 treats divided by 5.
Step-by-step explanation:
2(3x-5)=5x-3
6x -10 =5x -3
x=7
