MEASURE HT (NEED ASAP!!)

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

7 0

I think it might be 120 but get someone else’s opinion

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I need help please! l'm having trouble

Veronika [31]

Check the picture below.

6 0

3 years ago

Layla wants to build a wooden box with a volume of 450 cubic centimeters. She started with a width of 10cm and a height of 3cm.

puteri [66]

Answer:

Stop cheating and do your own work....

Mr E

Step-by-step explanation:

7 0

3 years ago

There were 200 people who voted at the town council meeting. Of these people, 40% voted for building a new basketball court in t

Nezavi [6.7K]

120 people
40% of 200 is 80
200-80=120
so 120 people voted against the basketball court

3 0

3 years ago

Read 2 more answers

If you were to draw three different parallelograms, each with a base of 6 units and a height of 4 units how would the areas comp

erma4kov [3.2K]

The areas would all be the same because they have the same side measurements.

Area = base x height

6 x 4 = 24 and will always be 24, so the area will always be 24.

3 0

3 years ago

Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man

Bess [88]

Answer:

$on \: this \: farm \: there \: are \to \\ \underline{ \boxed{17 \: pigs }}\: \\ and \\ \underline{ \boxed{28 \:chickens}}$

Step-by-step explanation:

$\\ \underline{ \boxed{solution \: to \: question \: \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\ hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\ while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \: of \: equations \: \\ to \: describe \: the \: situation \: is \to \\ \\ p + c = 45 \\ 4p + 2c = 124 \\ \\ \\ \underline{ \boxed{solution \: to \: question \: \boxed{B }}} \\ \\ \\ we \: could \: apply \: any \: of \: the \: simultanious \\ principles \to \\ here : am \: appling \: the \: elimination \: method \to \\ p + c = 45 \\ 4p + 2c = 124 \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124 \\ hence \to \\ - \frac{4p + 4c = 180}{4p + 2c = 124} \\next \to \\ 2c = 56 \\ c = \frac{56}{2} \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\ \boxed{p = 17}$

6 0

3 years ago