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2 years ago

PLLZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPP PLZZZZZZZZZZZZZZZZZZZZZ

Mathematics

2 answers:

MariettaO [177]2 years ago

6 0

Answer:

the answer is D 9w=21

how

21/9 = 2.3333333333

Step-by-step explanation:

den301095 [7]2 years ago

4 0

Answer: your answer is C. there is no common factor between 6 and 15.

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The mass of a ball is 128 g. It has a density of 0.5 g/cm³.

liraira [26]

Answer:

The volume of the ball is 256 cm³

Step-by-step explanation:

we know that

The density is equal to the ratio of the mass by the volume

D=m/V

Solve for V

The volume is equal to the ratio of the mass by the density

V=m/D

In this problem we have

m=128 g

D=0.5 g/cm³

substitute

V=128/0.5=256 cm³

7 0

3 years ago

CAN I PLSS GET HELP ASAP!!? What slope- intercept form equation represents the line

jasenka [17]

Answer:

y=-.5x+4

Step-by-step explanation:

7 0

3 years ago

Brainliest question please help me now plz

shutvik [7]

Answer:

5/12

Step-by-step explanation:

The tangent of an angle is the opposite side divided by the adjacent side, and in this case that would be 5 / 12. Hope this helps!

8 0

2 years ago

Read 2 more answers

If cosx is approximately 0.9511, what is the measurement of x to the nearest degree? Approximately, what is the sine of the angl

ziro4ka [17]

Answer:

Using the calculator angle whose cos is 0.9511 is 18 degrees

Sine of the complementary angle = 0.9511 also

Step-by-step explanation:

The sine of the complementary angle( which is 90-18 = 72 degrees) is same value 0.9511

8 0

3 years ago

Read 2 more answers

how to integrate <img src="https://tex.z-dn.net/?f=e%5E%7B2s%7D%20%2ACos%20%5Cfrac%7Bs%7D%7B4%7D" id="TexFormula1" title="e^{2s}

icang [17]

Answer:

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Step-by-step explanation:

Step(i):-

Given that $f(s) = e^{2s} cos\frac{s}{4}$

Now integrating

$\int\limits {f(s)} \, ds = \int\limits {e^{2s} cos\frac{s}{4} ds$

By using integration formula

$\int\limits { e^{ax} cos b x dx = \frac{e^{ax} }{a^{2}+b^{2} } ( a cos b x + b sin b x )$

Step(ii):-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{e^{2s} }{(2)^{2}+(\frac{1}{4}) ^{2} } ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(4+\frac{1}{16})} ( 2 cos (\frac{1}{4} ) s + \frac{1}{4} sin \frac{1}{4} s ))$

= $\frac{e^{2s} }{(\frac{65}{16} } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $16 X\frac{e^{2s} }{65 } ( \frac{8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s}{4} ))$

= $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

Final answer:-

$\int\limits {e^{2s} cos\frac{s}{4} ds$ = $\frac{4 e^{2s} }{65 } ({8 cos (\frac{1}{4} ) s + sin \frac{1}{4} s} ))$

6 0

3 years ago