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n200080 [17]
2 years ago
6

20.25 is what percent of 16?

Mathematics
2 answers:
Alisiya [41]2 years ago
7 0
79 percent i believe hope this helps
Law Incorporation [45]2 years ago
3 0

Answer:

126.5625

Step-by-step explanation:

An easy way to solve is to use the rule of three

20.25                                      x

                         =

16                                          100%

-> (20.25 x 100) : 16 = x

-> 2025:16= 126.5625

I hope this helps :0)

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Phoenix [80]

Answer:

A 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

Step-by-step explanation:

We are given that statistics students at the Air Force Academy (no kidding) purchased some randomly selected bags of cookies and counted the chocolate chips.

Some of their data are given below; 1219, 1214, 1087, 1200, 1419, 1121, 1325, 1345, 1244, 1258, 1356, 1132, 1191, 1270, 1295, 1135.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                          P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of chocolate chips = \frac{\sum X}{n} = 1238.2

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 94.3

            n = sample of car drivers = 16

            \mu = population mean number of chips in a bag

<em>Here for constructing a 95% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.131 \times {\frac{s}{\sqrt{n} } } , \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ]

                                   = [ 1238.2-2.131 \times {\frac{94.3}{\sqrt{16} } } , 1238.2+2.131 \times {\frac{94.3}{\sqrt{16} } } ]

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Therefore, a 95% confidence interval for the mean number of chips in a bag of Chips Ahoy Cookies is [1187.96, 1288.44].

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Answer:

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Step-by-step explanation:

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<em>The number of ways to listen to four CDs from a selection of 8 CDs.</em>

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