I presume you mean
x^(56) times x^(13) = x ^(56+13) = x^(69)
Answer:
Sheridan's Work is correct
Step-by-step explanation:
we know that
The lengths side of a right triangle must satisfy the Pythagoras Theorem

where
a and b are the legs
c is the hypotenuse (the greater side)
In this problem
Let

substitute

Solve for b





we have that
<em>Jayden's Work</em>


substitute and solve for c





Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle
<em>Sheridan's Work</em>


substitute

Solve for b





therefore
Sheridan's Work is correct
Answer:
Point O is the center of the circle.
<u>Part (a)</u>
is a chord.
is a segment of the radius and is perpendicular to 
If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).
Therefore, 
<u>Part (b)</u>
If
was extended past point E to touch the circumference it would be a chord.
As
is perpendicular to
, it would bisect the chord, but as
is only a portion of a chord,
<u>does not</u> bisect
.
Therefore, there is no length equal to
.
9,6^2+18,8^2=X^2
92,16+353,44=X^2
X^2=445,6
X=21