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Ksenya-84 [330]
2 years ago
8

NO ONEIS ANSWERING MY QUETION PLEASE ANSWER FOR 10 POINTS

Mathematics
2 answers:
Gennadij [26K]2 years ago
8 0

Answer:

I ate 50%

Step-by-step explanation:

i was hungry jeez.

Hatshy [7]2 years ago
7 0

Answer:

24.5

Step-by-step explanation:

+_+$+$+$-$-$-$+$+$+$+$+

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Is 8/9 greater than 5/10
Agata [3.3K]
Yes 8/9 is greater than 5/10
5 0
3 years ago
Read 2 more answers
−2x−(−5−4x)=−5(2x−7)
hoa [83]

Answer:

<em>x = 2.5</em>

Step-by-step explanation:

- 2x - ( - 5 - 4x ) =  - 5 ( 2x - 7 )

- 2x + 5 + 4x = - 10x + 35

- 2x + 5 + 4x = - 10x + 35

- 2x + 4x + 10x = 35 - 5

12x = 30

<em>x = </em>\frac{5}{2}<em> = 2.5</em>

Check the answer:

<em>L.H.S.</em> = - 2(2.5) - [ - 5 - 4(2.5) ] = <em>10</em>

<em>R.H.S.</em> = - 5 [ 2(2.5) - 7 ] = <em>10</em>

6 0
2 years ago
In a 3/4 measure, which part stands for the quarter note? 3 / 4 none
Lorico [155]

Answer:

i have no idea.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A yardstick casts a shadow of 24 in. at the same time a telephone pole casts a shadow of 20 ft 8 in. What is the height of the t
BabaBlast [244]
1 yd = 36 in;  20 ft 8 in = 248 in;
We will use a proportion:
36  : 24 = x : 248
24 x = 36 * 248
24 x = 8,928
x = 8,928 : 24 = 372
Answer:  C ) 372 in
5 0
3 years ago
How many ways can eight letters be arranged into groups of five where order matters and the first two letters are already chosen
fenix001 [56]

Answer:

120

Step-by-step explanation:

Since we're dealing with a problem where the order matters and the first two letters are already chosen we need to subtract the number of letters and the number of available slots per group.

We use the permutation formula to find the answer, but before that let's check values.

n = 8

k = 5

Now since there are two letters already chosen we have to deduct two from both the value of n and k.

n = 6

k = 3

Now we can use the permutation formula:

_{n}P_{k}=\dfrac{n!}{(n-k)!}

_{6}P_{3}=\dfrac{6!}{6-3)!}

_{6}P_{3}=\dfrac{6!}{3!}

_{6}P_{3}=\dfrac{6*5*4*3*2*1}{3*2*1}

The 3*2*1 cancels out and leaves us with:

_{6}P_{3}=6*5*4

_{6}P_{3}=120

So there are 120 possible ways to arrange eight letters into groups of five where order matters and the first two letters are already chosen.

6 0
3 years ago
Read 2 more answers
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