I'm guessing the question is meant to be "<span>If the radius of a circle with a area of 5.3 mm squared is multiplied by 5, what will the new area be?", so i'll answer that.
Area of a circle =</span>πr^2
5.3=πr^2, 5.3=π(5r)^2
132.5=25πr^2
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Answer:
x = -13/3 or -4 1/3 or - 4.333...333
Step-by-step explanation:
-5x - 16 = 8x - 3
-16 = 8x - 3 - 5x
-16 + 3 = 8x - 5x
-13 = 3x
x = -13/3 or -4 1/3 or - 4.333...333
... represents that it has infinite amount of 3's
Answer:
angle 1
Step-by-step explanation:
oksn ethe ansetware its 738wuy79q246978t59723482709uy783271-047892=-39074-2378904-2139047=123473192709270329742109372301790
Step-by-step explanation:
