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jarptica [38.1K]
3 years ago
15

In a group of 60 students, 18 students take algebra i, 20 students take algebra ii, and 10 students take both subjects. how many

students don't take either of these subjects?
Mathematics
1 answer:
nadya68 [22]3 years ago
8 0

Answer:

  32

Step-by-step explanation:

The number that take algebra i includes those who take both subjects, as does the number taking algebra ii. Then the number taking algebra i alone is ...

   18 -10 = 8 . . . . . take only algebra i

So the number taking any kind of algebra is ...

  20 + 8 = 28

and the number not taking either subject is ...

  60 -28 = 32 . . . not taking either subject

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0.2 in its simplest form as a fraction can be 2/10

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Solve the system.<br> 3x + 4y = 7<br> 2x-y=1<br> What does x and y equal
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Answer:

x=1 y=1

Step-by-step explanation:

Let's use the elimination method.
3x+4y=7
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11x=11
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Plug x=1 into either of the equations
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5 0
2 years ago
If rstu is a rhombus, then ___________________.
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3 0
3 years ago
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What is the perimeter? Please help
allochka39001 [22]

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5 0
3 years ago
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X+y+z=1
andrezito [222]

Answer: x = 0

y = 2

z = -1

Step-by-step explanation:

The system of equations are

x+y+z=1 - - - - - - - - - - 1

-2x+4y+6z=2 - - - - - - - - - 2

-x+3y-5z=11 - - - - - - - - - 3

Step 1

We would eliminate x by adding equation 1 to equation 3. It becomes

4y -4z = 12 - - - - - - - - - 4

Step 2

We would multiply equation 1 by 2. It becomes

2x + 2y + 2z = 2 - - - - - - - - - 5

We would add equation 2 and equation 5. It becomes

6y + 8z = 4 - - - - - - - - - 6

Step 3

We would multiply equation 4 by 6 and equation 6 by 4. It becomes

24y - 24z = 72 - - - - - - - - 7

24y + 32z = 16 - - - - - - - - 8

We would subtract equation 8 from equation 7. It becomes

-56z = 56

z = -56/56 = -1

Substituting z = -1 into 7, it becomes

24y - 24×-1 = 72

24y + 24 = 72

24y = 72 - 24 = 48

y = 48/24 = 2

Substituting y = 2 and z = -1 into equation 1, it becomes

x + 2 - 1 = 1

x = 1 - 1 = 0

4 0
4 years ago
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