Question

If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When will the object hit the ground?

Answer 1

Answer:

The object hits the ground after 3.52 seconds.

Step-by-step explanation:

The height of the object after t seconds is given by the following function:

$h(t) = -16t^2 + 198$

When will the object hit the ground?

It hits the ground when $h(t) = 0$. So

$-16t^2 + 198 = 0$

$16t^2 = 198$

$t^2 = \frac{198}{16}$

$t^2 = 12.375$

$t = \pm \sqrt{12.375}$

Since time is a positive measure, we only take the positive value

$t = 3.52$

The object hits the ground after 3.52 seconds.