In Functions and Function Notation, we were introduced to the concepts of domain and range. In this section, we will practice determining domains and ranges for specific functions. Keep in mind that, in determining domains and ranges, we need to consider what is physically possible or meaningful in real-world examples, such as tickets sales and year in the horror movie example above. We also need to consider what is mathematically permitted. For example, we cannot include any input value that leads us to take an even root of a negative number if the domain and range consist of real numbers. Or in a function expressed as a formula, we cannot include any input value in the domain that would lead us to divide by 0.
120
The original length is 12 and the width is 8 so
12 x 3+36
8x3=24
24+24+36+36+120
5,7,8 they all equal 21, 21 divided by 3 is 7
Adele's error was she should have multiplied the total of all the choices.
The point equidistant from a(2, -2) and b(-4, 6) is the midpoint
For (x₁, y₁) and (x₂, y₂) the midpoint is given by:
( (x₁ + x₂)/2 , (y₁ + y₂)/2 )
Midpoint = ( (2 + -4)/2 , (-2 + 6)/2 )
= ( (2 - 4)/2 , (6 - 2)/2) ) = ( -2/2, 4/2) = (-1, 2)
So the point equidistant from the two points is (-1, 2).
