Find ten rational number between –3and–2
1 answer:
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Answer:
Either y = or, y =
Step-by-step explanation:
We have to solve the following quadratic equation
45y² + 15y - 10 =0
Now, dividing both sides with 5 we get, 9y² + 3y -2 =0
Hence, to solve the above equation we have to factorize the left-hand part of the equation.
So, 9y² + 3y - 2 =0
⇒ 9y² +6y -3y -2 =0
⇒ (3y +2) (3y -1 ) =0
⇒ Either (3y +2) =0 or (3y -1) =0
⇒ Either y = or, y =
(Answer)
