Answer:
y = (1/3)x + 1
Step-by-step explanation:
You first find the slope:
(2 - (-1))/(3 - (-6)) =
3/9 =
1/3
This means the equation of the line is y = (1/3)x + b, where b is a real number.
Plug in either of the points to find the value of b:
-1 = (1/3)(-6) + b -->
-1 = -2 +b -->
1 = b
This means the equation is y = (1/3)x + 1
The number would be .5 I'm pretty sure
Answer:
The answer to your question is: Yes, x - 5 is a factor of the polynomial.
Step-by-step explanation:
To answer this question you need to divide the polynomial by the factor and if there is nothing left, they are factor.
<u>x³ -4x² -7x +10</u>
x -5
x² + x -2
x-5 x³ -4x² -7x +10
-x³ + 5x²
x² - 7x
-x² + 5x
-2x + 10
+2x -10
0 0 These zeros tell us that the linear
expression is a factor of the polynomial
Answer:
a) 37.31 b) 42.70 c) 0.57 d) 0.09
Step-by-step explaanation:
We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., 
= 35 and 
= 6. We know that the probability density function for a normal distribution with a mean of and a standard deviation of is given by
![f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%7D%5Csigma%7D%5Cexp%5B-%5Cfrac%7B%28x-%5Cmu%29%5E%7B2%7D%7D%7B2%5Csigma%5E%7B2%7D%7D%5D)
in this case we have
![f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B2%5Cpi%7D6%7D%5Cexp%5B-%5Cfrac%7B%28x-35%29%5E%7B2%7D%7D%7B2%286%5E%7B2%7D%29%7D%5D)
Let 
be the random variable that represents a row score, we find the values we are seeking in the following way
a) we are looking for a number 
such that
= 
, this number is =37.31
you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)
b) we are looking for a number 
such that
= 
, this number is =42.70
you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)
c) we find this probability as
=
you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)
d) we find this probability as
=
you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
