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Alina [70]
3 years ago
12

4Fill in the blanks to complete the following number patterns.13, 18,___, 31, 39, 49​

Mathematics
1 answer:
ella [17]3 years ago
7 0

Answer:

So you first count how much times the numbers go up,then you add the number you get it is 6+ you add them with 13 and you get 19.

Step-by-step explanation:

So you first count how much times the numbers go up,then you add the numbers so 1 is not enough 2 is not enough 3 is not enough 4 is not enough 5 is not enough 6 is enough, so we add the six with the number that we are adding which is 13,then you get 19

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Can you add additional information about the problem?
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42/40 into a mixed number is??
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Hello there!

So, as we see that 42 is more than the denominator, so, we would have to see by how much it would be over.

40-42=2.

So, sense we have an whole number which would be (1)

Your answer: \boxed{\boxed{\bf 1\frac{2}{40} }}
6 0
3 years ago
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Answer:

59

Step-by-step explanation:

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6 0
2 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
2 years ago
Math Help PLEASE ASAP
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 (B) Opposite sides are equal (otherwise, trapezoid, etc)
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3 years ago
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