Find all solutions in the interval [0, 2π). 4 sin2x - 4 sin x + 1 = 0

Mathematics

1 answer:

Eddi Din [679]2 years ago

5 0

Answer:

x = π/6, 5π/6

Step-by-step explanation:

4 sin² x − 4 sin x + 1 = 0

(2 sin x − 1)² = 0

sin x = ½

x = π/6, 5π/6

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