Find all solutions in the interval [0, 2π).
4 sin2x - 4 sin x + 1 = 0
1 answer:
Answer:
x = π/6, 5π/6
Step-by-step explanation:
4 sin² x − 4 sin x + 1 = 0
(2 sin x − 1)² = 0
sin x = ½
x = π/6, 5π/6
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