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2 years ago

What number is equivalent to 15 and 25

Mathematics

1 answer:

Gwar [14]2 years ago

3 0

Answer:

yo are you talking about like absolute value? then it's | -15 | and | -25 |

Step-by-step explanation:

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PLEASE HELP!!!! WILL MARK BRAINLIEST IF CORRECT!!!!!!

PilotLPTM [1.2K]

-2 would be your answer

7 0

2 years ago

12 girls are having a sleepover at a house, the food there can last them for 10 days. If 3 more girls came over, how long will f

FrozenT [24]

Answer:

The answer is 8

Step-by-step explanation:

12*10=120 120/15=8

8 0

3 years ago

please help, I do not know how to do this at all! A restaurant has a large goldfish pond. Suppose that an inlet pipe and a hose

Ne4ueva [31]

Answer:

H = 20.5 hours

I = 19.5 Hours

Step-by-step explanation:

Start by creating a system.

I = time which the inlet pipe takes alone to fill the pond

H = time which the hose takes alone to fill the pond

10/I + 10/H = 10

H - I = 1

H = 20.5 hours

I = 19.5 Hours

8 0

2 years ago

What is the answer ....?..?

drek231 [11]

Answer:

Step-by-step explanation:

hope it helps :)

7 0

2 years ago

It is known that the length of time that people wait for a city bus to arrive is right skewed with mean 6 minutes and standard d

Natali [406]

Answer:

The standard deviation of the sampling distribution of the sample wait times is of 0.8 minutes.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30. Otherwise, the mean and the standard deviations holds, but the distribution will not be approximately normal.

Standard deviation 4 minutes.

This means that $\sigma = 4$

A sample of 25 wait times is randomly selected.

This means that $n = 25$

What is the standard deviation of the sampling distribution of the sample wait times?

$s = \frac{4}{\sqrt{25}} = 0.8$

The standard deviation of the sampling distribution of the sample wait times is of 0.8 minutes.

4 0

2 years ago