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podryga [215]
2 years ago
10

What number is equivalent to 15 and 25

Mathematics
1 answer:
Gwar [14]2 years ago
3 0

Answer:

yo are you talking about like absolute value?  then it's  | -15 | and | -25 |

Step-by-step explanation:

You might be interested in
Bill and Mary Ann went to the Viola bakery. Bill bought 5 pies and 7 donuts for ​$12.65. Mary Ann bought 6 of each for ​$12.30.
sweet [91]

Answer:

Pies=$0.85

Donuts= $1.20

Step-by-step explanation:

In the equation let p stand for the number of pies and d stand for the number of donuts.

To solve this set up 2 equations, one representing bill and the other representing Mary Ann.

  • Bill's equation is 5p+7d=$12.65.
  • Mary Ann's equation is 6p+6d=$12.30

Then solve using a system of equations. Systems of equations can be solved using elimination or substitution. I will use substitution. Solve bill's equation for p. This gives you p=\frac{12.65-7d}{5}. Then, you can substitute that into Mary Ann's equation. This looks like 6\cdot \frac{12.65-7d}{5}+6d=12.3. Solve for d. Once you solve d=1.20. Finally, substitute 1.20 back into either Bill's or Mary Ann's for d and solve for p. No matter which equation you use p=0.85.

3 0
2 years ago
A consumer organization estimates that over a​ 1-year period 20​% of cars will need to be repaired​ once, 5​% will need repairs​
gtnhenbr [62]

Answer:

a) 0.5476

b) 0.0676

c) 0.4524

Step-by-step explanation:

Given this information, we can conclude that 74% of the cars won't need any repairs over a 1-year period (100 - 20 - 5 - 1 = 74%). And 26% will need at least 1 repair over a 1-year period.

P(car doesn't need repair) = 0.74

P (car needs repair) = 0.26

If you own two cars, the probability that:

<u>a) Neither will need repair:</u>

We need that car 1 won't need repair AND car 2 won't need repair.

=P(Car 1 doesn't need repair) x P(Car 2 doesn't need repair)

= 0.74 x 0.74 = 0.5476

The probability that neither will need repair is 0.5476.

<u>b) Both will need repair:</u>

We need that car 1 needs repair AND car 2 needs repair.

P(Car 1 needs repair) x P(Car 2 needs repair)

= 0.26 x 0.26 = 0.0676

The probability that both will need repair is 0.0676

<u>c) At least one car will need repair</u>

Car 1 needs repair or Car 2 needs repair or both need repair.

To solve this one, it's easier to use the complement of P(neither needs repair)

1 - P(neither needs repair)

1 - (0.74)(0.74)  = 1 - 0.5476 = 0.4524

The probability that at least one car will need repair is 0.4524

4 0
3 years ago
Yo If anyones awake i really need help
kirill [66]

Answer:

57

Step-by-step explanation:

Straight line value=180

Given Value=123

Value of ∆TKL

=180-123

=57(Ans)

3 0
3 years ago
I'm stuck on number 1 can somebody help me out?please☺
yuradex [85]
You have to find the common denominator which is 4 and multiply 26 by 4 which equals 104 add 3 which is 107 and divide by 4


Answer:107/4
7 0
2 years ago
BAC EDF BAC is 24 what is EDF
allochka39001 [22]

Answer:

6inches^2

Step-by-step explanation:

7 0
3 years ago
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