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Nonamiya [84]
2 years ago
6

Can somebody help me?

Mathematics
1 answer:
Andreas93 [3]2 years ago
6 0
The correct answer is letter D

Just believe me thats the correct answer
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The distance to the nearest exit doir is no more than 150 feet. Use d to represent the distance in feet to the nearest exit door
il63 [147K]

Answer: d\leq150

Step-by-step explanation:

1. You have the following information given in the problem:

- The distance to the nearest exit door is no more than 150 feet.

-  d represents the distance to the nearest exit door, in feet.

2. Therefore, keeping the information above on mind, you know that the  distance to the nearest exit door (d) must be less than or equal to 150 feet, then, you can express this as following:

d\leq150

5 0
3 years ago
What is the value of log5 125?
zhenek [66]

\rm log_{5}(125)  \\  \rm log_{5}( {5}^{3} )  \\  \rm1 \cdot3 \\ 3 \\  \therefore \tt log_{5}(125)  = 3

6 0
1 year ago
Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th
creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

C=A+B=(a_1+b_1,a_2+b_2)

And its magnitude is:

C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9

Where

a_1=Asinx

a_2=Acosx

b_1=Bsin(x+90)

b_2=Bcos(x+90)

Using the properties of the sum of two angles in the sin and cosine:

b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx

b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx

Sustituying in the magnitud of the sum

C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9

C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9

C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}

C=\sqrt{A^2+B^2} =9

Solving for B

A^2+B^2 =9^2

B^2 =9^2-A^2

Sustituying the value of the magnitud of A

B^2=81-5^2=81-25=56

B= 7. 4833

8 0
3 years ago
Researchers have found that after 25 years of age the average size of the pupil in a
laila [671]

Answer:

At 25 = 6.8612mm

At 50 years = 5.422mm

Step-by-step explanation:

Equation,

d = 2.115Logₑa + 13.669

d = diameter of the pupil

a = number of years

Note : Logₑa = In a (check logarithmic rule)

d = 2.115Ina + 13.669

1. At 25 years,

d = -2.115In25 + 13.669

d = -2.115 × 3.2188 + 13.669

d = -6.807762 + 13.669

d = 6.8612mm

At 25 years, the pupil shrinks by 6.86mm

2. At 50 years,

d = -2.1158In50 + 13.669

d = -2.1158 * 3.912 + 13.669

d = -8.2770 + 13.699

d = 5.422mm

At 50 years, the pupil shirks by 5.422mm

To save this question, I had to plug in the values into the equation.

Solving for Logₑa might be difficult, so instead I used Inx which is the same thing. Afterwards, i substituted in the values and solve the equation for each years.

8 0
3 years ago
Determine whether he fractions are equivalent<br> 10/15 and 12/18
ikadub [295]
10:15 12/18 fractures 15
7 0
2 years ago
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